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hey

just trying to figure out the array(words) does it mean that each index has a single sentence? or a single word?.

am using 4.2.2 which was available from dev c++.

hey guys
I am just curious and kinda puzzled can allegro library be used in Vista OS. I am pretty sure i installed it correctly through Dev c++.

Any comments would be fine, Thx

This is a good help..try searching the forum under usb

yes there is.

this works

char a[size]={'\0'};

are you trying to check wether the t value is a specific value if you are then i would suggest putting it in a if loop.

what he suggested, instead of using scanning through each character why dont you use

fgets where it grabs one line at a time.

gulp..idk.:((

is it?

1st scanf reads only the input

2nd one reads input and the next line?

while((ch=getchar())!= '\n')
i=1;

printf("%d \n", ch);

and

i=1;

while((ch=getchar())!= '\n')

ok


scanf("%d", &x);


x---> is a float and why are you using "%d" for a float?

shouldnt it be do with while loop.

while ((symbol=getch())!='a')
printf("ERROR");
printf("%c",symbol);

[array[i].field=symbol; /* file structure=array of records, where "field" is defined as char

shldnt it be getchar()....

I remeber doing a similar project where i used if loops thus defeining how to make the

array to print out

hi

what is variable k in your code? i mean why is it present there

its java code

if you want to print something in c use"printf();"

hmm it seems its your homework . Try writing any code then we can guide you

ok cool :)

your almost there actually, with your permission i can show you the code if you want to

understand the logic

i know but the question he asked was why was the presence of 4even and 5odd i just

showed him how to remove it.

as cas said c should be int

where c contains the ascII value of the variable

Then if you want to get the char again

use Putchar(c)

THIS IS NOT THE EXACT CODE.



ok here


printf("%d is %d", i, sum);

delete the 2nd %d and sum

ok almost there..but if you do that how will you retun either 1 or 0?.

try putting the if loop inside the main method ..

this loop explains by itself.


if(sum==1)
{
print number is even

i see what you mean

ok so the even function returns 1 for even number

and returns 0 for odd number.

so just put an if loop


printf("%d is %d\n", i, sum);

oh yea, my apologies just checked it out. thnx for the correction

for unix its ctrl+z i think

and windows ctrl+D, not totally sure

hmm can you post your code? I am not sure what the problem is