i buy ALL my software.
Type: Posts; User: Spectrum48k
i buy ALL my software.
after installing a game, everything runs smooth. after the computer
re-boots, it does not run anymore. i am trying to figure out what file
gets changed or re-placed after re-boot occurs. it is a...
the game is Far Cry.
P4 2.6 with 1gig Ram, Asus P4B800 with MSI 5900XT video.
I just did a complete hard drive format, installed XP SP1pro
and also installed latest video drivers and DX9b.
after installing games like...
1) spray with gasoline
2) light it up
3) enjoy the show
4) bring some marshmellows over, i hear they get a good taste from burning mainboards.
100% Software problem. period.
why does it run other games and not this ? the demo works
on my other computer. i understand the "division by zero" meening but not what could be wrong. memory, drivers ...
after installing FarCry Demo, i tried to run it and just before it goes to run, i get FloatingPoint erors Division by Zero Attempt. any ideas why ?
thnx in advance. :confused:
Hi all,
i recently installed a D-Link 604 (4port router + firewall) to add some extra protection to my home network. everything works fine except for my e-mail. what should i check for ? i know this...
i am trying to eliminate zeros and have no duplicate numbers on each line. this is where i am at now with no success. any help will be appreciated. i dont want to use 'goto' .
thnx..
...
thnx.
#include <stdlib.h>
#include <time.h>
#include <iostream>
using namespace std;
int main()
why am i getting the same numbers every time i run this
code ?
#include <iostream>
using namespace std;
if(tolower(*p1) != tolower(*p2)) break;
this is all i needed. as i said.. after 13 hours on the screen
i am lucky i can count to 3 nevermind see the brackets not needed.
thnx for the tips.
its been a looong day dude... my eyes are playing tricks..
thnx anyway..
this section of code does not compile:
if(tolower(*p1) != (tolower(*p2)) break;
the error is "missing ')' before 'break'
when i put the bracket before 'break' it compiles !
it shouldnt...
so since p=&x means p is pointing to th memory address
of x, any value i pass to p will go to the address of x, thus
manipulating x through its address. is this correct ?
i was wondering if someone can clarify something for me.
after declaring a pointer eg. int *p;
sometimes its assigned a value like p=x or
p=&x or *p=x
my question is this. i understand...
that makes sence.
this author cant make up his mind with new line character.
i use the double quote. in the book though, in every example
he seems to use one or the other. it can get frustrating...
whats the difference between "\n" and '\n'
single quote versus double for new line character.
they both do the same, but would one be used
for a specific application ?
thnx in advance.
it allocates memory continusly untill i get:
"system low on virtual memory"
now i know.. sometimes i just ask, even though the books are next to me.. sorry bout that ..
@hammer: why is this code amusing ?
while(TRUE)
{
malloc(10000);
}
its just to repeat a menu.
example:
code:
___________________________________________
for(;;){
do{
cout << "Help on:\n";
cout << " 1. if\n";
cout << " 2. switch\n";
this is what i ment ...
for(;;)
do{
.
.
.
.
}while(...)
does an infinite loop suck up computing cycles, thus slow
down program?
thnx in advance.
simplified code:
......
.....
for(;;){
do{
do c++ programs take longer to compile than equivalent programs writen in c ? (non OOP of course).
or is it just me, caught in a strange time warp :)
i started using a free visual c++ compiler and i find that when i change the code and goto re-compile under a diferent file name, i get errors in the code that dont exist if i close, and re-open the...