For (a little) more detail on how to get this sort thing working in C++ . . .
Due to Name mangling, C++ function names are changed to a form not easily rememberable. Therefore, instantiating a...
Type: Posts; User: Nightowl
For (a little) more detail on how to get this sort thing working in C++ . . .
Due to Name mangling, C++ function names are changed to a form not easily rememberable. Therefore, instantiating a...
Would "%02X" not work?
If the return value of fread is less than the total number that you asked for, then you're looking at an EOF being entered.
Make sense?
It returns the number of characters (excluding the EOF) that were successfully read.
. . . could be replaced by something like . . .
cat a.mp3 > output.mp3
cat t.mp3 >> output.mp3
. . . which is a little bit more efficient and smaller. ;)
Good question. I've no idea . . .
Well, it's a safe bet, that if fread returns EOF, then you've got less than 128 chars in there . . .
But, since the puts works correctly, I'd say it's nice...
You'll want strncpy instead of strcpy, I believe. No?
If you have a set of data . . . say, in an array of something much like this structure . . .
struct plot_point_t {
double xpos, ypos;
};
. . . then, it's really quite simple. Well,...
Correct, unless the original int value was less than 256, in which case the data will be unchanged.
EDIT: assuming you mean "cast it back to an int", not a uchar.
Well, something to consider is that you will want that code in a loop of sorts, such as . . .
(pseudocode, not real C!)
first = 1
do {
if(!first) explain_error()
print_prompt()
...
. . .
#include <stdio.h>
int main(int argc, char *argv[]) {
char s[128] = {0};
fread(s, sizeof(char), 128, stdin);
puts(s);
Yeah, that condition will always be true.
If you want to compare an int and a uchar, then something like this would work:
if((int)ucharvariable < intvariable) /* do stuff */
. . ....
. . . then it will continue to wait until 256 characters are in the buffer, I do believe. Why not try it yourself?
You may be wanting fgets instead?
If you're looking for something an append function for a string, go something like this.
int append(char *str, size_t strsize, char *toappend) {
if(str == NULL || toappend == NULL) return...
void process()
{
for (name; <10; name+1)
printf("Your name is %s/n",name);
}
That section has a few bugs in it . . .
First off . . . for (name; <10; name+1) is incorrect. Try for (;...
mpg123 is a linux mp3 player.
Well, it's quite simple.
Create a struct that stores the names and each value from the files, as well as the ID of that entry. Create an array of them. (Hopefully using memory allocation). Could...
What transgalatic is doing, is saying that it takes too much time to calculate the output in an exam, where everything is time-critical.
Try it for the cases of (1,1), (1, 2), (2, 1), (2, 2), (3,...
This problem is quite simple . . .
Assuming you're working a maximum size of, say, 32. (unsigned long int, in other words)
(yes, I *know* that long is the same thing as int on most modern...
As I pointed out in maybabier's other thread, there is a good guide to indentation here.
It really helps with debugging, trust me. The extra 20 seconds it takes to indent everything to the proper...
Isn't it already int?
Oh, whoops. My bad.
Yeah, getchar() returns an integer, and as vart points out, EOF is (usually) declared as -1. Therefore, if you typed in a 0xFF char (very unlikely...
I would highly recommend learning C *before* digging into how UNIX and operating systems work.
You end up learning how Linux works when you start digging into sockets and such in C anyhow. ;)
Read it into a character array like this . . .
(note that some of this is invalid, but changed for easier reading)
char number[1024];
scanf("%s", number);
/* and now you've got a nice,...
This is the most major disadvantage of using char *string = "STRING";.
Use something more like
char string[128] = "string";
. . . if you must.
Was there a purpose to that response? Is it asking for elaboration?
I'm going to assume so.
I'm also going to assume that this is homework. Therefore, I'm not going to give you a solution to...