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all you need to declare in this program is <iostream> and using namespace std;

and to stop the program from exiting before your ready use cin.ignore(2);
like this


cin.ignore(2);
return...

i would probably use switch/case. its pretty easy to understand



#include <iostream>
using namespace std;

int main()
{
double a,b,value;

wow thx so much it just clicked, your awsome!

I am dieing over this project. and whatever i put in doesnt seem to work please help!

//r = rows,s = stars, spl = stars per line



#include <iostream>
using namespace std;

int main()

where does it say only enter 5 numbers? and if your doing a loop i would do it like this



int input,least, greastest;

do
{
cout<<"Please enter a number.";
cin>>input;

you should not declare variables in a list like that. like this is cleaner: int sum,product,remainder,etc;
and i would try switching int to double

ok im sorry but the variables are: r = rows, s = stars, and spl = stars per line.

i keep trying to add 2 but then it just continues on.

Im studying loops and i have

#include <iostream>
using namespace std;



int main()
{
int r,s,spl,space;

u need to put cin.ignore(2); and then you will be able to see the results before the complier shuts it down. put it before the return 0; and it should work. and if you know you wont be using decimals...

I have this program i need help with. i have to make a program that will display this.

000000*
00000***
0000*****
000*******
00*********
0***********
*************

I have this project from school that has me program a code to tell the user if a given number is lucky or not. The number is lucky if it is a factor of 7, 11, or ends with a 7. I can do the first two...