Either precision in the language matters or it doesn't.
Type: Posts; User: cas
Either precision in the language matters or it doesn't.
Maybe at this point it should be noted that offsetof is neither a keyword nor a function, but a macro.
In general when the program exits, all memory will be reclaimed by the OS, so it's typically not something you need to worry about. That said, it's not bad practice to do so, and if this were a...
Because C does not prevent you from doing incorrect things, or at least doesn't make it hard to do incorrect things. The warning is correct and required: if you assign a const pointer to a non-const...
In main(), you need to assign a value to charCtr, since initially it will contain garbage.
By calling srand() in calcCollisionPayload(), assuming that time() returns the time in seconds, you will...
Given that the linker is providing prototypes (i.e. it's including parameter types), I'm inclined to think you're building with a C++ compiler, which encodes that information. Had you built with a C...
In a POSIX environment, system() just passes the string to /bin/sh, so you still have to worry about shell issues (what if the image name has a space in it, for example?).
If you want to safely...
First, it's probably a bad idea to name a header “math.h”, since that's a standard header name. You're already accidentally including the wrong header in runner.c when you use <> instead of "" to...
You're not giving “i” a value, so it's filled with garbage. A good modern compiler (e.g. gcc or clang) can warn about this:
t.c: In function 'recursiveLinearSearch':
t.c:50:1: warning:...
That condition is always true (if it's 'C' it's not 'c', and if it's 'c' it's not 'C'). You probably want &&.
Note: “this is not working” is not a good error report. You neglected to mention...
userName[i] != '\n' || userName[i] != '\0';
This will always evaluate to true. You want to use && instead of ||.
!isblank(userName[i]) || userName[i] != '\n'
Same here. Plus you're not...
Given two types T1 and T2, compilers are required to issue diagnostics (i.e. warning/error messages) if you assign T1* to T2* if T1 and T2 are not compatible types. Without going into smaller...
res->ai_addr has type struct sockaddr * (i.e. pointer to struct sockaddr).
You know that it is really pointing to a struct sockaddr_in *, because res->ai_family tells you so.
So you're not...
Once you've returned from the function that calls setjmp(), you can no longer jump to it; setjmp() relies on you to keep the function alive for a call from longjmp(). In a sense, setjmp() just...
First, #include <arpa/inet.h>, which is needed for inet_ntop().
You need to treat the struct sockaddr as the proper type, by casting it. Example:
inet_ntop(res->ai_family, &((struct...
This:
while(c=fgetc(fp)!=EOF)
Is equivalent to:
while(c=(fgetc(fp)!=EOF))
That'd be quite compiler/system dependent. Possibly your compiler inserts padding so that you're scribbling on unused memory for a few elements, before you start writing to critical areas.
Add...
int SIZE = 0;
int array[SIZE];
This is undefined behavior. You cannot have a zero-sized array. Even if you change the value of SIZE later, the array will not change to reflect that. The quick...
Use "bt" (backtrace) to find out where, in your code, the problem happened.
It looks like you're passing an invalid value to scanf() (or related function), though. Hard to say without seeing code.
Nope, can't be done.
You could probably cover most cases by using CUPS for the Unix side (including OS X) and whatever Windows does for the Windows side. That shouldn't be too onerous.
The condition in line 29 (i < n) is wrong; neither i nor n changes in the loop, so the result will always be the same. Presumably you meant to use "k", not "i".
Your compiler has to be warning you about an invalid call to ArrayScan() (if it's not, it's broken, and you should get a new compiler).
You're passing &array to ArrayScan(). array has type int*,...
Then you're either using a C++ compiler or a terrible C compiler. I'd guess the former. If you're learning C, configure your compiler to be a C compiler not C++ (it might be as easy as naming the...
A few things.
*(c+x) can be written c[x], which tends to be easier to read.
getchar() does not return '\0' to mean “end of input”. Rather, it returns EOF; if you want to stop when the user...
atoi() is undefined if the result does not fit into an int; lots of systems will reduce it modulo 2**32, but that's not a requirement. Also, int need not be 32 bits wide (it could be smaller or...