You're allocating memory (using new) in remove(), but not deleteing it anywhere. That's a memory leak.
Type: Posts; User: noodles
You're allocating memory (using new) in remove(), but not deleteing it anywhere. That's a memory leak.
You're returning the vector by value. There's no problem in that since it's being copied back in the calling function.
If you want to print "True" if the first element matches, put a break after the printf ("True.\n\n"); (within proper braces, of course).
It seems more likely that you want to print "True" when...
(Looks more like C than C++)
Your third for loop contains the assignment operator, and not the comparison operator. You're assigning the elements of setB to the elements of setA and then using the...
It's most probably not a bug.
You must be relying on dangling pointers, uninitialized variables, or something like that somewhere.
Go through your code and make sure that you're not doing...
It shouldn't happen. Try posting some code so that we can have a look.
For printing, using only setprecision is not enough:
double a = 50.0 / 3.0;
cout << setprecision(3);
cout << a << endl;prints 16.7.
You'll need to use the "fixed" manipulator...
Do you need something like this?
int NumPrompts;
cout << "Please enter the number of prompts you desire: ";
cin >> NumPrompts;
int i=0;
while (i++ < NumPrompts)
{
...
Everything works fine for me (after adding a few missing semicolons). Did you try re-compiling?
It is, but I meant that there isn't any portable way for ALL the types, including the signed ones, as the OP wanted.
For integral types, see the macros defined in <limits.h>
e.g. 'INT_MAX', 'INT_MIN', etc.
For real number types, see the macros in <float.h>,
e.g. 'FLT_MIN', 'FLT_MAX', etc.
That's the ONLY...
>from what I know, ++(postfix) has higher precedence than *, why I do not get *p1++=300?
Since that is the postincrement operator, it performs the increment on the address AFTER the expression has...
Replace that code with:
printf("The word %s backward is ", word);
for (i = strlen(word)-1; i >= 0; i--)
printf("%c", word[i]);
printf("\n");
There's pow.
I think you mean "by value".
You cannot change the base address of an array, if that's what you're trying to do. Also, the array "changed_data" will no longer be accessible after the end of the function call. Try updating values...
Hope the following code helps:
for (i=0; i<MAX; i++)
{
for (j=0; j<MAX; j++)
my_arraystr[i][j] = my_array[i][j]+'A';
my_arraystr[i][j] = '\0';
}
It's good that you showed us your attempt.
Here are some suggestions for improving your code:
1. Use meaningful variable names.
2. Understand the difference between == (a comparison operator)...
You aren't reading the data properly into an array. I've changed the code to the following and it works (hopefully :) ):
/*My comments are in red*/
#include <stdio.h>
#include <stdlib.h>...
Try this:
#include<stdio.h>
int home,work;main(){for(home+=49; home<=53; home++){for(work=49;work<=home;work++)putchar(home);
puts("");}for (home-=2; home>=49; home--){for (work=49; work<=home;...
Go through the following code. If you have any questions, please don't hesitate to ask!
#include <stdio.h>
#include <ctype.h>
int main()
{
int num;
printf("Please enter a digit from 0...
I tried using RSS a few times, but soon realized that it is USELESS.
It's printing 0 infinitely because you're not passing the incremented value to test in the recursive call.
To make it work use
test(++count); /*pre-increment*/
instead of
test(count++);...
No, printf() uses %f for floats and doubles.
> c = 170; /* generates compiler overflow warning */
It's not an overflow: you're assigning an out-of-range value.
You're assigning a value in the range 0..UCHAR_MAX to a variable that can...