Remember, for four items, n*n/2 = 8 and n*log2(n) = 8
The sorts that are more efficient at larger sizes tend to also do extra things that the O(n*n) sort doesn't need to. Like walk through a list to...
Type: Posts; User: iMalc
Remember, for four items, n*n/2 = 8 and n*log2(n) = 8
The sorts that are more efficient at larger sizes tend to also do extra things that the O(n*n) sort doesn't need to. Like walk through a list to...
Forget Bubble Sorting in this instance. While that's easy to implement for an array, it's hideously difficult to implement correctly for a linked-list, assuming you do it by re-linking the list's...