Re : Logic problem

Dear All,

I don't understand why the following function is wrong, can anyone tell me :

void check(int a) {
if (a / 2 == 1)
printf("a is odd\n");
else
printf("a is even\n");
}

Thanks a million.

Best regards,
Wah

If you think about it carefully, a number / 2 == 1 is not working. What if the number is 11 ? 11 / 2 = 5. I think you wanna do somethin like this:

Code:

---

checkEven( int a )
{
  if ( a % 2 == 0 )
      return 1;
  else
      return 0;
}

---

Code:

---

void check(int a)
{
  if (a % 2 == 1)
    printf("a is odd\n");
  else
    printf("a is even\n");
}

---

-Prelude

isn't that the same as my one lol?

Yes, but we posted at approximately the same time.

-Prelude

>void check(int a) {
>if (a / 2 == 1)
>printf("a is odd\n");
>else
>printf("a is even\n");
>}

A logical answer why this is wrong:

a / 2 = 1 if and only if a = 2

By the way, in your function 2 is odd. :-)