Lottery game

I'm creating a lottery game that solicits 6 numbers from the user between 1-59 and then generates 6 numbers until they all match. When I compile and run my code it takes the user input fine. However as it runs through i want it to display what number its on and then keep going until it finds a match to the numbers. However when i do run it the code is just a line of long numbers and thats it. Any suggestions?

Code:

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#include "stdafx.h"
#include <iostream>
#include <ctime>
#include <string>
using namespace std;

void getnums(int[]);

int main()
{
        srand((unsigned) time(0));
        const int MAXNUM = 6;
        int count = 1;
        int total = 0;
        int x, n, nums[MAXNUM];
        int lotnums[MAXNUM];
        for(x=0;x<MAXNUM;x++)
        {
                cout << "\nPlease enter number " << x+1 << " : " ;
                cin >> nums[x];
                if ((nums[x] > 59) || (nums[x] < 1))
                {
                        cout << "\nThat is not a valid entry." << endl;
                        x=x-1;       
                }

        }

getnums(lotnums);

        for (x=0;x<MAXNUM;x++)
                        for (n=0;n<MAXNUM;n++)
                        if (lotnums[x]==nums[n])
                        {
                                cout << nums[0] << " " << nums[1] << " " << nums[2] << " " << nums[3] << " " << nums[4] << " " << nums[5] << endl << endl;
                                cout << lotnums[0] << " " << lotnums[1] << " " << lotnums[2] << " " << lotnums[3] << " " << lotnums[4] << " " << lotnums[5] << endl << endl;
                                cout << "/n/n Congratulations you just won the lotttery. It took " << total << " attempts." << endl << endl;
                        }
                        else if (lotnums[x]!=nums[n])
                        {
                                getnums(lotnums);
                                total+=count;
                                cout << total;
                        }
                                return 0;
}



void getnums(int lotnums[])
{
        lotnums[0] = 1 + rand() % 59;
        do
                lotnums[1] = 1 + rand() % 59;
        while (lotnums[0] == lotnums[1]);
        do
                lotnums[2] = 1 + rand() % 59;
        while ((lotnums[0] == lotnums[2]) || (lotnums[1] == lotnums[2]));
        do
                lotnums[3] = 1 + rand() % 59;
        while ((lotnums[0] == lotnums[3]) || (lotnums[1] == lotnums[3]) || (lotnums[2] == lotnums[3]));
        do
                lotnums[4] = 1 + rand() % 59;
        while ((lotnums[0] == lotnums[4]) || (lotnums[1] == lotnums[4]) || (lotnums[2] == lotnums[4]) || (lotnums[3] == lotnums[4]));
        do
                lotnums[5] = 1 + rand() % 59;
        while ((lotnums[0] == lotnums[5]) || (lotnums[1] == lotnums[5]) || (lotnums[2] == lotnums[5]) || (lotnums[3] == lotnums[5]) || (lotnums[4] == lotnums[5]));

        return;
}

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Your code prints out the lists everytime any number in the first set matches any number in the second set, not when all six are matched.

Edit to add: if you're willing to deal with the STL, then std::set may be just the thing for you.

ok then so how would i make it cout the count and then keep giong until all six numbers match?

So inside your loop all you do is check whether that particular number is a match, so you might do something like numMatched++ when you find a hit. (Make sure you reset numMatched to 0 before you start.)

Then, after all your for loops have run, either numMatched==6, print and be done, or numMatched < 6 in which case you add 1 to total and do it again.