strange grammar about volatile and operator overload

Hello everyone,


The following code,

Code:

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operator const Outer::Inner * volatile & ();

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1.

I think it means an operator &, which returns const Inner* type and takes no arguments, right?

2.

Adding volatile to return value means?

(I previously only used volatile to qualify variable)


thanks in advance,
George

It's an operator that converts to a reference to a volatile pointer to a const Outer::Inner.

Thanks grumpy,


To make your sentence complete, convers (from current type) to a volatile pointer to a const Outer::Inner, right?

Quote:

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Originally Posted by grumpy

It's an operator that converts to a reference to a volatile pointer to a const Outer::Inner.

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regards,
George

You left out the words "to a reference" which is implied by the ampersand at the end, but yeah.

Yes, grumpy!


It is my mistake. The complete sentence is, convers (from Outer type) to a reference of volatile pointer to a const Outer::Inner. Right?

Quote:

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Originally Posted by grumpy

You left out the words "to a reference" which is implied by the ampersand at the end, but yeah.

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regards,
George

Well, we don't know what it converts from, because we don't have the context. It converts from whatever class it is a member of.

Thanks CornedBee,

Quote:

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Originally Posted by CornedBee

Well, we don't know what it converts from, because we don't have the context. It converts from whatever class it is a member of.

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Understand. My question is answered.


regards,
George