cin >> something

Can someone tell me why is it

Code:

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cin >> something

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, where something is a variable, and not

Code:

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cin << something

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???

Because, I got confuse with the cout object as cout uses the symbol <<. Thanks in advance :D

The "arrow" created by ">>" or "<<" indicates which direction the data goes. So "cout << x" sends the value of x to the output, "cint >> x" takes the input and fills it into x.

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Mats

Quote:

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Originally Posted by matsp

The "arrow" created by ">>" or "<<" indicates which direction the data goes. So "cout << x" sends the value of x to the output, "cint >> x" takes the input and fills it into x.

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Mats

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OMG, matsp, you're a really good programmer and explainer (althought there is no such word in dictionary). I've finally understand =) THANKS!