Loops: The 'any' inquiry

Alright, in this situation I want to take a program that I wrote and modify it so it can take an integers and if any of the numbers are negative, it returns a negative number, but if all the numbers are positive, it returns their average. This is the program I would like to modify:

Code:

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/*        This program is a test driver for anyPositiveEOF.
          Written by: Chubbs1900
          Date: 12-01-2007
*/
#include <iostream>
using namespace std;

#ifndef TRUE
        #define  TRUE  1
        #define  FALSE 0
#endif

//        Prototype Statements
        bool anyPositiveEOF (void);

int main (void)
{
//        Statements
        cout << "Enter numbers <EOF> to stop:\n";
        cout << "anyPositiveEOF is: " << anyPositiveEOF () << endl;
        return 0;
}        // main

/*        ================= anyPositiveEOF ==================
        Read number series & determine if any are positive.
          Pre  Nothing
          Post  Returns true  if any numbers >  0
                Returns false if all numbers <= 0
*/
bool anyPositiveEOF (void)
{
        bool anyPositive = false;
        int  numIn;
        while ( !anyPositive && (cin >> numIn) )
            anyPositive = (numIn > 0);
        return anyPositive;
} // anyPositiveEOF

/* Results:
Enter numbers <EOF> to stop:
-1
-2
3
anyPositiveEOF is: 1

Enter numbers <EOF> to stop:
-1
-2
-3
^danyPositiveEOF is: 0
*/

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Quote:

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Code:

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#ifndef TRUE
        #define  TRUE  1
        #define  FALSE 0
#endif

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you don't need that. There is a native "bool" type in C++.

as for how to know if theres any neg #,

Code:

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bool anyNegativeNumber = false;

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change it to true when you encounter one.
Then

Code:

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if (anyNegativeNumber) {
..
}

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You don't need the void in parenthesis either for that matter.

Is this just a ported C program? That's the idea I get.

Quote:

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Originally Posted by iMalc

You don't need the void in parenthesis either for that matter.

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Correct. C++ and C have different meanings for empty ()'s in a function definition.

AFAIK, () and (void) are the same thing in C++, but not in C.

Quote:

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AFAIK, () and (void) are the same thing in C++, but not in C.

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I believe they have the same meaning in C++ and C in a function definition, but not a function prototype.