Hi-lighting Or Similar

Given a 2D array which is initialised with the following numbers:

int list[3][8] = 1, 2, 3, 4, 5, 6, 7, 8;
9, 10, 11, 12, 13, 14, 15, 16;
17, 18, 19, 20, 21, 22, 23, 24;
a loop then iterates every combination and outputs:

1, 2, 3, 4, 5, 6, 7, 8
1, 2, 3, 4, 5, 6, 7, 16
1, 2, 3, 4, 5, 6, 7, 24
1, 2, 3, 4, 5, 6,15, 8
1, 2, 3, 4, 5, 6,15, 16
and so on......... ending with
17, 18, 19, 20, 21, 22, 23, 24.


Question is:-
I need to hi-light (or use someway) to be able to have 3 selected numbers
in the output. The selected numbers are: 1, 3, 5, 8, 9, 11, 13, 16, 17, 19, 21, 24
Any combination that has 3 of these numbers is to be outputted.
I am unable to find anything in C that will hi-light these numbers. Do I need to
learn visual basic, C#, does Dev-C++ have an option, or have I missed an algorithm in C that can do this? Thanx, Rossco

Which OS/Compiler are you using?

Yes you can highlight text on a console, but I know of at least 3 different ways (no, make that 4 different ways) of achieving it.
But there isn't a single way which is a guaranteed "works with every system".

I am using Dev-C++ compiler to all my work. As a beginner I haven't yet progressed to windows app. to do any work. Thus far I think this compiler with C coding will meet my needs. The more I think about it, an algorithm would be more efficient. I'm sure there's a mathematical genius here somewhere?

Here's a part of what I've accomplished thus far:-

Code:

---

int main()
{
    int a, b, c, d, e, f, g, h, i, j;
    i = 0;
    int list[3][8];
       
list[0][0]= 1, list[0][1]= 2, list[0][2]= 3, list[0][3]= 4, list[0][4]= 5, list[0][5]= 6,
                                          list[0][6]= 7, list[0][7]= 8;
list[1][0]= 9, list[1][1]=10, list[1][2]=11, list[1][3]=12, list[1][4]=13, list[1][5]=14,
                                          list[1][6]=15, list[1][7]=16;
list[2][0]=17, list[2][1]=18, list[2][2]=19, list[2][3]=20, list[2][4]=21, list[2][5]=22,
                                            list[2][6]=23, list[2][7]=24;   
   
             
    for(a=0; a<3; a++)
    for(b=0; b<3; b++)
    for(c=0; c<3; c++)
    for(d=0; d<3; d++)
    for(e=0; e<3; e++)
    for(f=0; f<3; f++)
    for(g=0; g<3; g++)
    for(h=0; h<3; h++)
   
fprintf(fptr,"&#37;4d%4d%4d%4d%4d%4d%4d%4d\n",list[a][0],list[b][1],list[c][2],list[d][3],
                                                                                  list[e][4],list[f][5],list[g][6],list[h][7]);
 
    system ("PAUSE");
    return 0;   
    }

---

so, the output needs to include 3 numbers (1,3,5,8,9,11,13,16,17,19,21,24) with the remainder of each line resulting in 5 other numbers listed.
This is a personal project, I have no aspirations of becoming a programmer.
Keep Well, Rossco.

Is this the kind of thing you want to achieve?
http://www.adrianxw.dk/SoftwareSite/...Consoles4.html

Well! Giving this problem further consideration, I find it more prudent to focus on a C algorithm to include into the Fn rather than trying to learn a new application and language. If other languages have a function(Fn) that allows for hi-lighting, then that algorithm must be portable, even in part and usable in C.
Correct me if I'm wrong.... there must be a code in C somewhere that would allow for 3 of the numbers previously mentioned to be included into each line outputted?

You can format the output however you want with the standard output functions.
All you need to do is figure out which variables are involved.

I had a look at the site you suggested, code was in C++ tho' Thanx Salem. I'm still persevering, and revueing previous programs. There's a key somewhere near.