Confused with array size

Hi,

I'm starting to get confused here..if I want an array to hold 2 values, then should I write int values[1] or int values [2] ? I'm confused because of the 0 index.

Also, when I wish to have an array of string, then is it just char values[n][20] (where 20 is the number of maximum characters and n is how many strings I have in the array) ?

You should write:

Code:

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int values[2];

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But if you want to access those elements of the array, it would be values[0] and values[1]. values[2] does not exist.

Declare with the number of elements you want. If you declare n elements, then you have elements ranging from index 0 to n-1, inclusive.

Quote:

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Originally Posted by desmond5

Hi,

I'm starting to get confused here..if I want an array to hold 2 values, then should I write int values[1] or int values [2] ? I'm confused because of the 0 index.

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As everyone mentions, the syntax is array[length_of_array] and then you have length_of_array-1 elements because they count from 0.

Quote:

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Also, when I wish to have an array of string, then is it just char values[n][20] (where 20 is the number of maximum characters and n is how many strings I have in the array) ?

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The syntax would be, I believe, char values[num_of_string][length_of_strings];

It's easier I believe, to think of a 2d array as being Array[rows][columns]. Internally, the compiler handles this quite differently, but it can be thought of thematically, as rows and columns, and was designed with that in mind.