Memo Box to Binary

Hi,

Not sure if this is meant for the windows section or C++ but sorry if it is in the wrong section

i was wondering if anyone can help me with a problem i have.

what i want is the user to open a file (this file will only have 1 word on it for now opening the file is not a problem as this is already been done) the file will then open in the memo box.

now when the user presses a button the 2nd memo box will convert what is in memo 1 into binary i also have a mini binary program but that only looks for what the user inputs.

can anyone help me?

I'm pretty sure I could help if I actually understood the question !?!

--
Mats

ok ill try and explain it a bit better

1# i will have 2 memo boxes on a form.

2# 1 of the memo boxes will have a button to load a txt file.

3# the txt file will then be displayed in memo number 1

4# there will also be an additional button that the user can press

5# once this button has been press all the text from the txt file that has been loaded into memo 1 will then convert into binary format and display in memo number 2

Hope this helps explain what i am trying to achieve a bit more

at the moment i have managed to do points 1 to 3.

So, you can't add an additional button, or you can't translate a ascii text into binary [and by this, I suppose you want sets of 8 digits 0..1 that represent each letter in the text?].

E.g. ABCD would be

Code:

---

01000001 01000010 01000011 01000100

---

So give us a sample of what you think this should look like. Or look at "recent posts by Salem" where he gives some examples of how to do binary to text and text to binary - under the subject of "bit stuffing".

--
Mats

well i want the button to translate what is in memo1 into binary and display it in memo 2. just like you have put ABCD.

i have a binary program but that just looks at a string that has already been created. this is the code i have for the binary program

Code:

---

int main()
{
  string name("test");
  vector < bitset<8> > b;

  for (int i=0; i<name.length(); i++)
      b.push_back(name[i]);

  for (int i=0; i<b.size(); i++)
      cout << b[i] << endl;

      cin.get();

}

---

but obviously this looks at the string i have entered but i need to to read all the charactures that will be loaded in memo1.

I'm not that familiar with how you get values out of and into different fields in a form - but surely that's not terribly hard?

--
Mats

well the next thing i have managed to do is transfer the data from one memo to the other one by using this code

Code:

---

Memo2->Lines = Memo1->Lines

---

so im just trying to find a way to get it to convert into binary using that button.

So, you need to use "memo1->lines" as input to the code you have above (instead of "name"), and instead of doing cout of it, create a string of the binary value. You could replace cout with a stringstream and then get the string out of stringstream and put that into memo2->lines.

--
Mats

I'm not sure what your "goal" is, but I suggest you try looking at a Hex Editor. A hex editor will show your file in hexadecimal, and alongside the hex, it will display the characters for any values in the ASCII range. It doesn't know if the value represents an ASCII character, but whenever it sees 41 (hex), it will also display an 'A', etc.

I assume that a hex editor is not exactly what you want, but I think it will give you some ideas.

Hexadecimal is frequently used in place of binary, because binary gets hard to read, write, or speak, especially when you are dealing with more than 8 bits. (And, binary isn't built into cin or cout.)

You can easily learn to convert between hex and binary in your head. You only have to learn 16 conversions, and it does not require any calculations! You already know zero and one, and several of the other bit patterns are easy to learn, because they make "nice patterns". i.e. 0101 (binary) = 5 (hex), and 1010 (binary) = A (hex)... These are easy patterns to remember.


You simply group the binary data into 4-bit nibbles (or nybbles) like this:

0000 0000 0000 0101 (binary) = 0005 (hex) = 0005 (decimal)
0101 0000 0101 0000 (binary) = 5050 (hex) = 20,560 (decimal)
0101 0101 0101 0101 (binary) = 5555 (hex) = 21,845 (decimal)

Or, with your "ABCD" example:

'A' (ASCII) = 0100 0001 (binary) = 41 (hex) = 65 (decimal)
'B' (ASCII) = 0100 0010 (binary) = 42 (hex) = 66 (decimal)
'C' (ASCII) = 0100 0011 (binary) = 43 (hex) = 67 (decimal)
'D' (ASCII) = 0100 0100 (binary) = 44 (hex) = 68 (decimal)

...Wherever you see 0100, it converts to 4, whenever you see 0101 it converts to 5... Wherever you see 1010 it converts to A... Wherever you see 0111 it converts to 7, etc. Very easy!

(I used a calculator for the decimal conversions.)