pass a 2d array to function which takes an array of pointers as argument?

So what I want to do is something like that:

Code:

---

void function(char *ar[]){
    strcpy(ar[0],"blablabla");
}
int main(){
    char str[100][200];
    function(str);      //wrong
}

---

I mean I want to have a function to which i can pass a 2d array and it ll make some changes to it. I do not want a function with a 2d array argument cause i do not want to set the size of array explicitly, so I believe this is the only way. The thing is that

function(str);

is wrong and I get a warning during compile:

test.c:9: warning: passing argument 1 of function from incompatible pointer type

so what I 'm asking is, what is the right way to call function on this array or/and if there is another way to do all this.
thanks.

void function(char ar[][200])
is all you need.

> I do not want a function with a 2d array argument cause i do not want to set the size of array explicitly
Tough luck for you then.
http://c-faq.com/aryptr/ary2dfunc2.html
Whilst you can do it by this trick, you lose the true 2D array subscripting in the process and you have to do it all by hand.