Fill the blanks in the program...

Hai friends i am new to this forum . I have one problem please solve it ...

Code:

---

#include<stdio.h>
void fun(.........);/*fill the blanks in this line*/
main()
{
int *p=1000;
fun(..........);/*fill the blanks in this line*/
printf("%d\n",*(int*)p);
}
void fun(..........)/*fill the blanks in this line*/
{
.........
........./*fill the function body*/
}

---

friends this is the program you should not change any lines in this program and you want to fill the blanks which i had mentioned as (..........). And i need 2000 as the output from the printf in main.....
Please solve it....

Are you sure that is what you were given? It looks wrong to me.

--
Mats

Yes this what the interviewer had given to me....

And do you actually think that if you can't solve this task, you should have the job?

--
Mats

I tryed many things but i am not able to solve it.Please solve it...

Post your best attempt so far.

Hai friends i had tryed this but i got the segmentation fault

Code:

---

#include<stdio.h>
void fun(int **q);
main()
{
int *p=1000;
fun(p);
printf("%d\n",*(int*)p);
}
void fun(int **q)
{
**q=2000;
}

---

Try removing one of the stars in fun().

Edit: And there are more things wrong: You need to pass &p to fun(), and printf shouldn't have *(int *)p, but just p.

--
Mats

I had tryed this also but i am getting the same error . And you had told that to change in printf . But it is not possible they gave me the conditio that i should not change any line given by them

Code:

---

#include<stdio.h>
void fun(int *q);
main()
{
int *p=1000;
fun(&p);
printf("%d\n",*(int*)p);
}
void fun(int *q)
{
*q=2000;
}

---

Ah, ok. It's a bit more complex then...

You'll have to set *q = <some static variable>; and make the static variable 2000. And you DO need two ** on q into fun, and a &p when you call fun.

--
Mats

Can you please write the program....I am not able to get it....

It would seem that your program stub is fundamentally flawed before you've even begun.

> int *p=1000;
This gets me
warning: initialization makes pointer from integer without a cast
You can't just invent memory addresses and expect to be able to use them.

> printf("&#37;d\n",*(int*)p);
Here you're dereferencing the pointer (which is currently pointing at some hard coded address).

So you need to do two things
1. Make p point to an actual integer, not just some invented address 1000
2. Make the integer being pointed to contain the value 2000

Post #7 was sort of on the right lines.

Don't take the job.

I am new at programming and even I can tell you that this code is seriously wrong. Also if you can't figure it out, then don't take the job as this is probably the minimum requirement for the job... Just my opinion on this. Lemme try tearing this up.

Code:

---

#include<stdio.h>


void fun(.........);/*fill the blanks in this line*/
main()
{

int *p=1000;  <-- you declare an address but no variable to take it. You cant imagine an address out of nowhere.

This is what it is saying, "int (address?) = (undefined)pointer -> 1000;"

fun(&p);
printf("&#37;d\n",*(int*)p);
}
void fun(int *q) <--- why use q now when you could redefine p?
{
*q=2000;
}
}

---

I can't guarantee that what I noted was correct, but I think it is in the step in the right direction. Dont take the job mate if you can't do this minimum problem.

I thought that this forum members will help me to understand this full program . But no one is helping....So ok...