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With x = 0101 1111 1011 1110 0100 0000 0000 0000(two) and
y = 0011 1111 1111 1000 0000 0000 0000 0000(two), and
z = 1101 1111 1011 1110 0100 0000 0000 0000 0000(two)
representing single precision IEE 754 floating-point numbers, perform, showing all work:
a) x + y
b) (result of part a) + z
c) Why is this result counterintuitive?
a) i got 2.74x10^10
b)z is -2.74x10^10
so the reult is 0
c) i don't see why it's counterintuative
Because I'm lousy at doing floating point math by hand, I wrote a little program:
The output is:Code:// fpnum.cpp : Defines the entry point for the console application.
//
#include <iostream>
#include <cmath>
using std::cout;
using std::endl;
union floatint {
float f;
int i;
};
const int xi = 0x5FBE4000; // 0101 1111 1011 1110 0100 0000 0000 0000
const int yi = 0x3FF80000; // 0011 1111 1111 1000 0000 0000 0000 0000
const int zi = 0xDFBE4000; // 1101 1111 1011 1110 0100 0000 0000 0000
int main(int argc, char* argv[])
{
floatint x, y, z;
x.i = xi;
y.i = yi;
z.i = zi;
cout << "x = " << x.f << endl;
cout << "y = " << y.f << endl;
cout << "z = " << z.f << endl;
float a = x.f + y.f;
cout << "a) x + y = " << a << endl;
float b = a + z.f;
cout << "b) a + z = " << b << endl;
return 0;
}
I guess the reason it may be counterintuitive is that adding a number to another number and then subtracting the first number (or adding a negative version of it, as in this case) should result in something other than zero - becasue b is non-zero, right?Code:x = 2.74179e+019
y = 1.9375
z = -2.74179e+019
a) x + y = 2.74179e+019
b) a + z = 0
And the reason for this is as I stated earlier: The numbers are normalized, so the 1.9375 is shifted right to match up with 2.74179e+19, which makes it zero (because 0.00000....00019375e+19 is too many digits to fit in a 32-bit float.
[It seems like you got the exponent wrong in your conversion - or you typed it wrong]
--
Mats
You can look at it this way,
(x + y) + z = 0
but...
(x + z) + y = 1.9375
Addition is (normally) an associative/commutative operation, that is, A + B + C = (A + B) + C = A + (B + C) = (A + C) + B, etc... But in this case, depending on the order of operations for the addition, you can get different results.
Good explanation. Thanks for the clarification.Quote:
Originally Posted by hk_mp5kpdw
--
Mats