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When I run it, it lists the row but some number appears at the end! From where, why?
Code:#include <stdio.h>
void main()
{
int sranje;
int a,rez, n=5;
int polje[100];
for(a=1;a<=n;a++)
{
printf("Unesite %d. polje: ", a);
scanf("%d", &polje[a]);
}
rez = funk(polje, n);
printf("%d", rez);
scanf("%d", &sranje);
}
int funk(int polje[100],int n)
{
int a;
for(a=n;a>0;a--)
{
printf("\n%d", polje[a]);
}
}
* Don't use void main(), see the FAQ http://faq.cprogramming.com/cgi-bin/...&id=1043284376
* Arrays in C are 0-based, not 1 based, ie they start at 0.
* Avoid sscanf, perhaps flush the input before you ask for a number (use fgets and sscanf). See http://faq.cprogramming.com/cgi-bin/...&id=1043284385 and http://faq.cprogramming.com/cgi-bin/...&id=1043284392
You seem to start at an index of 1 when you get input, yet you wind back to 0 when you print it.
You are not returnning anything from Funk() so printing out 'rez' is just going to display whatever random crap was left in that part of memory.
but i cant return array, can I?I would need to store array in some other variable?
No, I think what mike_g was saying is that you are not returning anything from the function, but you are printing a variable that is set to the return value FROM the function - this return value will be some "rubbish" that is essentially whatever happens to be in the register that is used for passing return values - could be almost any value (and it's most likely your mystery number).Quote:
Originally Posted by shardin
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Mats
How does that even compile? It should give you an error about funk() not having a return statement shouldn't it?
Depends on what the flags he invoked the compiler with. But it should at least give him a warning, even on the lowest warning level.
Most compilers only warn, not error for "missing return" paths, but I agree that having some warnings enabled would be a good thing for ALL users of compilers.Quote:
Originally Posted by cpjust
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Mats