using double codes in assigning value to an int variable

Code:

---

main()
{
  int i = "a";
  printf("%d      %c",a,a);
  getch();
}

---

the output shows a no. 170 and a ASCII character corresponding to it. Even if we change the character we get the same no. 170. I know I am int variable wrongly but it is just a curiosity why does it shows 170. If we use float or char variable it shows an error.
I am usinng turbo c++ in windows xp.

thanks a lot
bye n take care

All you're printing is the address of where the string is stored.
Or in the case of %c, the LSB of the address, expressed as a char.

Since the compiler seems to put the first string it finds in the same place in memory, the actual content of the string is irrelevant.

I would dought that program will atleast compile. a is a variable which us undeclared. Din't your compile complain you anything about.

ssharish2005

@Salem Thanks Salem, I somewhat understood your point, one thing is still there, why does using int variable does not give a error but using float or char gives error.

@ssharish2005, the compliler doesn't give any error in this case, but if we use float or char in place of int then it gives error.

Yeah, there is so much wrong with the code that analysis is nigh on impossible.
It was probably just typed from memory, rather than a more accurate copy/paste from the code editor.

Quote:

---

Originally Posted by hitesh_best

@Salem Thanks Salem, I somewhat understood your point, one thing is still there, why does using int variable does not give a error but using float or char gives error.

@ssharish2005, the compliler doesn't give any error in this case, but if we use float or char in place of int then it gives error.

---

He was asking where 'a' came from (the variable),

Code:

---

main()
{
  int i = "a";
  printf("%d      %c",a,a);
  getch();
}

---

But I assume you meant to print i not a

Probably because your ancient compiler will silently convert a pointer to an int without complaining.

In short there is a big difference between double quotes " and a single quote '

To the original poster: If you enable WARNINGS in your compiler, it will definitely tell you that you are converting a pointer into an integer, which is probably not really what you wanted.

--
Mats

Oh yes, there is a mistake in the code.

It should have been variable i in the print statement, instead of a.

Quote:

---

Originally Posted by hitesh_best

Oh yes, there is a mistake in the code.

It should have been variable i in the print statement, instead of a.

---

which means you actually posted the code without even looking at it once or bothering to compile it?
Or just typed it from memory and never bothered to check it.