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Quick question. If I have a global variable and a local variable with the same name and I use the variable which is used? Does the local variable take precedence or the global variable. Is 50 or 100 printed from the example below?
Code:int x = 50;
void foo()
{
int x = 100;
cout<<x;
}
You get the local version by default. You can access the global version of x by using ::x instead of x (the :: is called the scope resolution operator).
In general, this should never occur. Your variables should have names such that a conflict between a local and a global variable cannot occur.
> Is 50 or 100 printed from the example below?
Did you try it?
They really shouldn't have the same name, as was mentioned earlier, but if you wanted to find out do what Salem said ^^ there.
One thing though, as standard practice, you should never ever use a global variable. It tends to create the potential for your program's stability to be compromised. Attributes that belong to a class should always exist as private attributes, and you should only ever be able to access them via methods and friend functions.
Although about which comes first.. Its all about scope. Which ever has the most recent scope (or the smaller scope I guess) Global has the scope of the entire class, next is method scope, then you can have if/while/for scopes. If you redefine it in the smallest end of the scope (which is the if/while/for), it'll take precedence over method and global. Hope that makes sense :P