Progress of program

I am working on the interface of the program. Cause it takes long time to run, I am thinking of having a progress bar, which it shows how many percentage it completed. For example, after

cout<<"20% is completed"

, may I ask how I can erase it and replace with

cout<<"21% is completed" afterward?

Many thanks and I appreciate any help.

Here's a nice quick one:

Code:

---

while (progress <= 100)
  cout<< progress << "% is completed\r";

---

If you mean actually writing on the exact same line, I don't think that is possible in plain, vanilla C++ (using the standard library). You would need to write your own code in the specific-O/S manner required to get greater control over the console, or use a library which ends up doing that for you.

Code:

---

#include <iostream>
#include <string>
#include <sstream>
using namespace std;

int main()
{
    string first, second;
    stringstream fs;

    first = "It's ";
    second = "&#37; done.";


    cout << first;

    for(int i=0; i<100; i++)
    {
        fs=""; //apparently this is incorrect... no operator= for that
        fs << i << second;

        cout<<fs.str;
        //do stuff
        for(int j=0; j < fs.length(); j++) cout <<'\b'; //nonexistent member function
    }

    cout<<"done    "<<endl;
    return 0;
}

---

something like this... can somebody help me to get this to compile with just using C++ constructs?

Something like

Code:

---

for(int i=0; i<100; i++)
{
        stringstream fs("");
        fs << i << second;

        cout<<fs.str;
        //do stuff
        for(int j=0; j < fs.str.length(); j++) cout <<'\b';
}

---

?

yes, except:

Code:

---

cout<<fs.str;
some.cc:22: error: no match for 'operator<<' in 'std::cout << fs.std::basic_stri... etc... lots of ugly type-stuff

and

for(int j=0; j < fs.str.length(); j++) cout <<'\b';
some.cc:24: error: insufficient contextual information to determine type

---

This compiles and works fine

Code:

---

#include <sstream>
#include <iostream>
//#include <windows.h> Sleep is used to emulate time consuming operation

int main()
{
        for(int i=0; i<100; i++)
        {
                std::stringstream fs;
                fs << i << "&#37; done.";

                std::cout << fs.str();
                //do stuff
                //Sleep(100); time consuming emulation
                for(int j=0; j < fs.str().length(); j++) std::cout <<'\b';
        }
        return 0;
}

---

Very nice. One problem is that it just goes to 99&#37; when of course it should go to 100%.

I've never had much success at all with using '\b' to clear console output. Nice to see this work. :)

arr.. dang parentheses!! thanks vart! I'm so used to C...

thanks mac... if you mean me... haha... but when it's 100, you don't need it anymore. :)

something I found out is that \b doesn't clear it, you have to overwrite it. Thus all the spaces in the last cout.