An Interesting Code Sample

Code:

---

class Base{
pulbic:
        void foo() const{
                cout<<"Base Class: void"<<endl;
        }

        int foo() {
                cout<<"Base Class: int"<<endl;
                return 1;
        }
};

int main(){

Base test;
test.foo();
 return 1;
}

---

It can pass compiling. But how does the compile know which function I want to call?

In other words, how can I call the function
void foo() const ?

Call foo() with a const reference.

Code:

---

#include <iostream>

using namespace std;

class Base{
public:
        void foo() const{
                cout<<"Base Class: void"<<endl;
        }
        int foo() {
                cout<<"Base Class: int"<<endl;
                return 1;
        }       
};
int main(){
    Base test;
    test.foo();
   
    const Base & b = test;
    b.foo();   
    return 1;
}

---

my output

Code:

---

Base Class: int
Base Class: void

---

Kurt

To avoid confusion, you just shouldn't try to overload functions based on return type. Overloads based on const-ness are normal though (the [] operator usually).