Pass an array to a function by reference?

Is it possible to pass an array by reference to a function?

Like so...

Code:

---

void clearboard(int& sqr[])
{
    for (int i=1; i<11; i++)
        sqr[i] = 'X';
}

void board(int& sqr[])
{
    cout << sqr[1] << " | " << sqr[2] << " | " << sqr[3]
          << sqr[4] << " | " << sqr[5] << " | " << sqr[6]
          << sqr[7] << " | " << sqr[8] << " | " << sqr[9];
}

int main(int argc, char *argv[])
{
  int sqr[10];
  clearboard(sqr);
  board(sqr);
  system("PAUSE");       
  return 0;
}

---

For some reason it wont let me compile it...

Quote:

---

declaration of `sqr' as array of references
In function `void clearboard()':
`sqr' undeclared (first use this function)
(Each undeclared identifier is reported only once for each function it appears in.)
At global scope:

---

Arrays are passed by reference automatically, no & needed.

Also note that your for loop is incorrect. It should stop at i < 10, since sqr has a size of 10 and indexes start at 0.

Oh right didn't know that... thanks, :)



Thanks didn't see that... stupid mistake... lol

To just answer the question :)

Code:

---

void func(char (&arr)[1024])
{
}

---

reference to an array of 1024