switch function

hi my program keeps skiping my switch function any ideas??

Code:

---

int main (void)
{
  people datab;
  store tdata;
  char any;
 
  char choice;
  char choice2;
  float count = 0;
  float count2 = 0;
  int c;
 
  tdata.clearary();
 
  cout<<"\nThis program will allow the user to create and then control a database. \n";
 
 
  cout<<"what would you like to do? \n To enter a new record press n \nTo delete a record press d \nTo view a full list of the users with details press f \nTo view serch options press s\n to quit press q :- ";
  cin>>choice;
 

 while(count == 0)
 {
      choice = getchar ();
          switch(choice)
          {
            case 'n':
                {   
                      system("cls");
                          tdata.load();
                      tdata.enter(1);
                          tdata.save();
                  count = 1;
                  break;
                }
               
            case 'd':
                {
                  //delete a record ??
                  count = 1;
                  break;
                }
               
                case 'f':
                {
                  system("cls");
                  tdata.list();
                  count = 1;
                  break;
                }

---

p.s this is just a snipit also using quincy

Choice will be '\n' the first time in the loop. You're not handling that case.
Kurt

could you explain how

Code:

---

  cin>>choice;

---

will read a char and leave '\n' in the buffer.

Code:

---

choice = getchar ();

---

getchar will return '\n'.
Kurt

so how do i fix that

I would remove the

Code:

---

cin>>choice;

---

Kurt

but wouldnt that stop me getting the users answer

Code:

---

choice = getchar ();

---

Should reads the users choice as well.

BTW it is never a good idea to mix c-style with c++ style IO.

Kurt

could you fix this for me as well as that worked fine

Code:

---

char k = 'y';
        while (k == "y");

---

If you use doublequotes, the char inside will be treated as a C-style string. That's wrong, although the compiler might be extra smart about it. Use single quotes for single chars.

Code:

---

while (k == 'y') {

---

That shouldn't compile.
try

Code:

---

        char k = 'y';
        while (k == 'y'); // this would be an infinite loop. Do you really want the ;

---

Kurt

thanks i didnt notice that

k i got it mostly working but for some reason the first two questions print in a single line

Code:

---

void people::enter(int i)
  {
    char k = 'y';
        while (k == 'y')
          {
            cout << "Enter the name of the person ";
            gets(np[i].name);
        cout << "Enter the phone number of the person ";
            gets(np[i].phone);
                cout << "Enter the full address of the person ";
                gets(np[i].address);
                cout << "Enter the Email address of the person";
                gets(np[i].email);
                cout << "enter the name of the party that the person belongs to ( conservative, labour, liberal, other)";
                gets(np[i].party);
                cout << "Do you wish to enter another member ? (y/n)";
                cin  >> k;
                }
        }

---

any idea

Let me guess. Before calling that function you are using getchar() to read a character.
You will have to get rid of a leftover '\n' in the input buffer.
cin.ignore() could help.
Kurt