No clue how to do this....

I know how to write basic stuff to a file but I'm having a problem.

In my main function a .txt file is opened up to write data to. The main function creates some objects that are output by using a print function.
Code:

object.print();

The problem that I'm having is that I can't figure out a way to write the data to the same file. The way the program is going to work is the file is always going to be the same name and I can't pass that name as a variable. So I tried just opening up that file in the object member function print's code and appending data to it but that did not work. What's a good way to go about doing this?

I have a main function:

Code:

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ofstream csis;

int main(){

    csis.open("csis.dat");

    Do Stuff...

    cout << stuff; //outputs stuff to the terminal window
   
    csis << stuff; //writes the same stuff to the file

    Object fun;

    fun.dosomething(x,y);

    fun.print(); //this is where the problem comes in

    csis.close()
}

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The Object member function print looks like this:

Code:

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void Object::print(){

    cout << something; //outputs something to the terminal window;

    csis << something; //I want to somehow write this to the same file/append it to the file

}

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Note: I've already overloaded << operator for a different reason and it can't be changed. No parameters can be passed to the print function. The data file will be the same file everytime though. I tried to just make the code open up that same file again and append to it but it only appends at the very end of the program and then it just looks like it dumps a buffer it had filled up.

If you use the flush manipulator on the stream, it will flush it to the file.

Code:

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cout << something << flush;  // flush to cout's stream (default stdout)
csis << something << flush;  // flush to csis's stream (your file)

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Quote:

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The problem that I'm having is that I can't figure out a way to write the data to the same file. The way the program is going to work is the file is always going to be the same name and I can't pass that name as a variable. So I tried just opening up that file in the object member function print's code and appending data to it but that did not work. What's a good way to go about doing this?

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In my opinion, there is no good way to go about doing this due to the artificial restrictions that your teacher created. I am loathe to suggest this, but I think you have two choices:
1. Make csis a member reference variable. Use the constructor to pass csis when you instantiate the object. The bad part is that your object now can be modified by modifying csis from outside (e.g., from the main() function).

2. Create an ofstream local to your print() member function. The bad part is that you probably have to hardcode the filename, and you have to consider things like having to append the content instead of overwriting.

Quote:

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Originally Posted by laserlight

In my opinion, there is no good way to go about doing this due to the artificial restrictions that your teacher created. I am loathe to suggest this, but I think you have two choices:
1. Make csis a member reference variable. Use the constructor to pass csis when you instantiate the object. The bad part is that your object now can be modified by modifying csis from outside (e.g., from the main() function).

2. Create an ofstream local to your print() member function. The bad part is that you probably have to hardcode the filename, and you have to consider things like having to append the content instead of overwriting.

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I've already tried your second suggestion and I get the same result. I guess I can try your first one and see what's happening.

Quote:

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and I get the same result.

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What is that, exactly? I thought before it was this :

Quote:

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I tried to just make the code open up that same file again and append to it but it only appends at the very end of the program and then it just looks like it dumps a buffer it had filled up.

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You just need to flush buffers to stop that... with flush...

Could you be more precise?

If print can't take any parameters, may-be the constructor can? Or may-be you might use a static variable for the filename.

Quote:

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The data file will be the same file everytime though. I tried to just make the code open up that same file again and append to it but it only appends at the very end of the program and then it just looks like it dumps a buffer it had filled up.

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I don't get this. If the print() function opens a hard-coded file for appending, the file should be closed and flushed automatically when the function ends.

I'll try a static variable. I'm not sure if it will go over too well. I have to declare it in the object class and not in main though.

Wiiire: I tried using flush and it did the same thing as you quoted.

Here's to be more specific:

Code:

---

ofstream csis;

int main(){

    csis.open("csis.dat");

    Do Stuff...

    cout << stuff; //outputs stuff to the terminal window
   
    csis << stuff; //writes the same stuff to the file

    Object fun;

    fun.dosomething(x,y);

    cout << stuff;

    csis << stuff;

    fun.print(); //this is where the problem comes in

    cout << stuff;

    csis << stuff;

    .
    .
    .

    // This patter repeats itself about 20 times.

    csis.close()
}

---

The end result would look like this in the file:

Code:

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1 stuff
2 stuff
3 stuff
4 stuff
.
.
.
19 stuff
20 stuff

17 print //output from the print function (first appearance)
18 print
19 print
20 print

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It is absolutely unclear what you are trying to do and your code snippet doesn't tell what is wrong with it.
Rather than trying out random ideas, try to think what you are exactly supposed to do. Using a global stream like that doesn't seem like a very good idea. Are you supposed to do all the printing to the file inside the class member?

You should have an ofstream variable inside the print function. You should open the file in that print function with ios::app so that it appends. When the function ends, the ofstream variable will be destroyed, which will flush the contents to the file and the close it.

My guess is that your problem is that you are opening the file in more than one place. You should only be ever opening that file in the print function. If you open it also in main (like in that code snippet) then you will be having the same file open twice. Also notice that in that code snippet, you are not opening the file for appending, so hopefully you did that correctly in your print function.

So forget the rest of the stuff and implement the printing by opening the file in the print function. If that doesn't work, post that code and somebody might be able to help.

It is opened in the main function. So should I just close it in the print function and then reopen it?

If you need to write to it in the main function, you should open it (in append mode), write to it and close it immediately.

Your print function should open it and write to it and close it immediately as well.

When you create a local ofstream variable in the function, then it is closed automatically when the function ends. But the main function doesn't end until the end of the program, so it doesn't close automatically. You have to call close() yourself to ensure that your print function can open and write to it properly.

Normally, you would pass the ofstream by reference to the print function, it is only because your requirements state that the filename should be hardcoded in the print function do you have to worry about this. Of course, if you weren't also writing to the same file in main it would be easier as well.