Printable View
how would you write an if statement to determine whether or not it is a leap year. A year is a leap year if it is evenly divisible by four hundred or if it is evenly divisible by four, but not by one hundred
i tried to start it like so
Code:if (((((year/400)%2)== 0)||((((year/4)%2)== 0)&&(((year/100)%2)!= 0)))&&((month==2)&&(day==29)))
Code://if year is evenly divisible by 400 OR year is evenly divisible by 4 AND year is not evenly divisible by 100
if(year%400 == 0 || year%4 == 0 && !(year%100 == 0))
You might want to write this asQuote:
Originally Posted by The Brain
since not everyone knows off the top of their head that && has higher precedence than || (I had to look it up).Code:if (year%400 == 0 || (year%4 == 0 && year%100 != 0))
Edit: If efficiency matters, you can also rewrite it as
since the first condition is much more likely to be true, allowing the || shortcutting to skip the second condition. The two conditions for && should be left as is, since the first one is much more likely to be false, allowing the && shortcutting to skip the second one.Code:if ((year%4 == 0 && year%100 != 0) || year%400 == 0)
thnx. i think i was thinking too hard
I feel the same way when it comes to womenQuote:
Originally Posted by radiantarchon28
GCC actually gives a warning about this is you pass it -W -Wall. (That is, || and &&s without parentheses.)Quote:
since not everyone knows off the top of their head that && has higher precedence than || (I had to look it up).