array of characters ending after a space

Hey all,
I'm relatively new to C, although I'm very familiar with PHP, so I'm aware of the general constructs of C. However...I'm having a small problem with an array of characters in a struct. When scanf'ing to the struct the array is ending after any 'spaces' in the string. For example if I were to enter my full name, it would simply display "Richard".
This struct / string is also a part of a linked list, so I'm not sure if this might be causing a problem?

Heres the overall view of whats happening...

Code:

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typedef struct T_Lecturer {
  char Name[25];
} LecturerInfo;

typedef struct T_PtrNode {
  LecturerInfo Lecturer;
  struct T_PtrNode *Next;
} LecturerNode;

int main() {
  LecturerNode *NewEntry;

  NewEntry = malloc(sizeof(*NewEntry));
  if (NewEntry != NULL) {
      printf("Name: ");
      // John Smith
      scanf("%s", NewEntry->Lecturer.Name);
  }
  printf("%s", NewEntry->Lecturer.Name);
  // John
}

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Thanks in advance,
Richard.

scanf will do that. You'd have to use fgets to get the whole string.

Also, in this line :

Code:

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NewEntry = malloc(sizeof(*NewEntry));

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Don't you mean to do :

Code:

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NewEntry = malloc(sizeof(LecturerNode));

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Quote:

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Don't you mean to do :

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Why bother? Original variant should automatically ajust if the pointer type changes

Quote:

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Originally Posted by Happy_Reaper

scanf will do that. You'd have to use fgets to get the whole string.

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I'll give it a go :)

Quote:

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Originally Posted by Happy_Reaper

Also, in this line :

Code:

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NewEntry = malloc(sizeof(*NewEntry));

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Don't you mean to do :

Code:

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NewEntry = malloc(sizeof(LecturerNode));

---

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Hmm...would make more sense I guess :)

-Update-
fgets() works, but its now saving 25 bytes, including the '\n', making it very difficult to include it in a sentence (unless there is a string function to trim it?)

With regards to altering the sizeof()...I tried LecturerNode and it ignored the 2nd input. I'll leave it as *NewEntry, it works, and doesn't cause any problems. :)

Quote:

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fgets() works, but its now saving 25 bytes, including the '\n', making it very difficult to include it in a sentence (unless there is a string function to trim it?)

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A common way to get rid of the \n at the end of the input is to just turn the \n into a \0:

Code:

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char str[25];

fgets(str, sizeof(str), stdin);
if(str[strlen(str)-1] == '\n')
  str[strlen(str)-1] = '\0';

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more common way is shown in the FAQ

Quote:

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Originally Posted by vart

more common way is shown in the FAQ

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Which thread are you referring to.

http://faq.cprogramming.com/cgi-bin/...&id=1043284385

Quote:

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Originally Posted by vart

http://faq.cprogramming.com/cgi-bin/...&id=1043284385

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Awesome, thanks :)