How to use pointers in this case?

I have the following code

Code:

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#include <stdio.h>

typedef struct
{
        char nume[60];
        char sectie[20];
        int grupa;
} student;

int schimb (student *faculta)
{
  faculta[1]->grupa=6;
return 0;}

int main()
{student faculta[3];
  faculta[1].grupa=5;
  schimb(&faculta[1]);
  printf("%d",faculta[1].grupa);
return 0;}

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the code shell only change the value of faculta[1].grupa using the function schimb.
How can I make this code work ?

Code:

---

#include <stdio.h>

typedef struct
{
        char nume[60];
        char sectie[20];
        int grupa;
} student;

void schimb (student *faculta)
{
        faculta->grupa = 6;
}

int main( void )
{
        student faculta[3];

        faculta[1].grupa=5;

       
        printf("Before: %d\n",faculta[1].grupa);
        schimb(&faculta[1]);
        printf("After:  %d\n",faculta[1].grupa);

        return 0;
}

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What you passed into the function was one value of the array. Not an array in itself. I also did some formatting ... makes it look nicer.

Quote:

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How can I make this code work ?

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What do you want to do?

Quote:

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Originally Posted by 7stud

What do you want to do?

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Ok and how do I pass into the function the whole array and not only a value of the array ?

Code:

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void display( int arr[], int length)
{
        for(int i = 0; i < length; ++i)
        {
                cout<<arr[i]<<" ";
        }
       
        cout<<endl;
}


int main()
{
        const int SIZE = 3;
        int myArray[SIZE] = {10, 20, 30};
        display(myArray, SIZE);

        return 0;
}

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