How do I display char 2darray in string form?

The function like this

Code:

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#include <stdio.h>
#include <stdlib.h>
#define MAX_NAME 25
int main()
{
        char **name;
        int i;
        scanf("%d", &n);
        name = malloc(n * sizeof *name);
        for (i = 0; i < n; i++)
                name[i] = malloc(MAX_NAME * sizeof *name);
        for (i = 0; i < n; i++)
                scanf("%s", &name[i]);
        for (i = 0; i < n; i++)
                printf("%s", name[i]);

        return 0;
}

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This is display

Code:

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4
abc
def
ghi
jkl
Segmentation fault

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I just wanna display the array of name. Where is the wrong? Can do this, char *name[25], instead of n column and 25 row?

n is undeclared.

I don't think this does what you want.

Code:

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scanf("%s", &name[i]);

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Get rid of the &.

You should also free your memory when you're done with it.

[edit]

Quote:

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Can do this, char *name[25], instead of n column and 25 row?

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Why don't you try it and find out? :) Yes, you can, if you mean instead of char **name. [/edit]

Code:

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name[i] = malloc(MAX_NAME * sizeof *name);

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* sizeof *name isn't what you're probably wanting to use here, your gonna get alot more memory than your expecting (probably 4 times more)

just malloc(MAX_NAME); will suffice

> name[ i ] = malloc(MAX_NAME * sizeof *name)
name[ i ] = malloc(MAX_NAME * sizeof *name[ i ]);

Remember,
p = malloc ( n * sizeof *p );