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Numbers To words
hey um i kind of been trying to figure this out for awhile now...well the program is supposed to convert numbers like 123 into words such as one two three the only problem is my program writes the numbers back words such as three two one...does anyone have any ideas of what i can change or add to make these numbers come out foward in my program? im also kind of like a beginer at this so i need all the help i can get
Code:
#include <stdio.h>
void main() {
int temp, num, count, i, reg[5], remainder;
char *word[11] = {"one ","two ","three ","four ","five ","six ","seven ","eight ","nine "};
printf("Enter Number\n");
scanf("%d",&num);
temp = num;
count = 0;
while(temp !=0)
{
remainder = temp % 10;
temp = temp / 10;
reg[count] = remainder;
++count;
}
for(i=1; i<=count; ++i) {
switch(i){
case 1:
switch(reg[0]){
case 1:
printf("%s",word[0]);
break;
case 2:
printf("%s",word[1]);
break;
case 3:
printf("%s",word[2]);
break;
case 4:
printf("%s",word[3]);
break;
case 5:
printf("%s",word[4]);
break;
case 6:
printf("%s",word[5]);
break;
case 7:
printf("%s",word[6]);
break;
case 8:
printf("%s",word[7]);
break;
case 9:
printf("%s",word[8]);
break;
default:
printf("Zero");
break;
}
break;
case 2 :
switch(reg[1]){
case 1:
printf("%s",word[0]);
break;
case 2:
printf("%s",word[1]);
break;
case 3:
printf("%s",word[2]);
break;
case 4:
printf("%s",word[3]);
break;
case 5:
printf("%s",word[4]);
break;
case 6:
printf("%s",word[5]);
break;
case 7:
printf("%s",word[6]);
break;
case 8:
printf("%s",word[7]);
break;
case 9:
printf("%s",word[8]);
break;
default:
printf("Zero");
break;
}
break;
case 3:
switch(reg[2]){
case 1:
printf("%s",word[0]);
break;
case 2:
printf("%s",word[1]);
break;
case 3:
printf("%s",word[2]);
break;
case 4:
printf("%s",word[3]);
break;
case 5:
printf("%s",word[4]);
break;
case 6:
printf("%s",word[5]);
break;
case 7:
printf("%s",word[6]);
break;
case 8:
printf("%s",word[7]);
break;
case 9:
printf("%s",word[8]);
break;
default:
printf("Zero");
break;
}
break;
case 4:
switch(reg[3]){
case 1:
printf("%s",word[0]);
break;
case 2:
printf("%s",word[1]);
break;
case 3:
printf("%s",word[2]);
break;
case 4:
printf("%s",word[3]);
break;
case 5:
printf("%s",word[4]);
break;
case 6:
printf("%s",word[5]);
break;
case 7:
printf("%s",word[6]);
break;
case 8:
printf("%s",word[7]);
break;
case 9:
printf("%s",word[8]);
break;
default:
printf("Zero");
break;
}
break;
case 5:
switch(reg[4]){
case 1:
printf("%s",word[0]);
break;
case 2:
printf("%s",word[1]);
break;
case 3:
printf("%s",word[2]);
break;
case 4:
printf("%s",word[3]);
break;
case 5:
printf("%s",word[4]);
break;
case 6:
printf("%s",word[5]);
break;
case 7:
printf("%s",word[6]);
break;
case 8:
printf("%s",word[7]);
break;
case 9:
printf("%s",word[8]);
break;
default:
printf("Zero");
break;
}
}
}
}
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Right now, you make it into a string as you go backwards (starting at 1's place and going up) and convert it immediately. You could convert it first, then go forward through the string. Note that blocks like this
Code:
switch(reg[0]){
case 1:
printf("%s",word[0]);
break;
case 2:
printf("%s",word[1]);
break;
case 3:
printf("%s",word[2]);
break;
case 4:
printf("%s",word[3]);
break;
case 5:
printf("%s",word[4]);
break;
case 6:
printf("%s",word[5]);
break;
case 7:
printf("%s",word[6]);
break;
case 8:
printf("%s",word[7]);
break;
case 9:
printf("%s",word[8]);
break;
default:
printf("Zero");
break;
Can be reduced to
Code:
printf("%s", word[reg[0] - 1]);
Or just add zero into your array and then
Code:
printf("%s", word[reg[0]]);
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