Printing a return value

How can one print the return value of a function? For example, you have an 'Add' function which returns the sum of two argument integers. However, when you return a value, and run the function, the value is not printed. So what is the best way to print such a value?

I know I could do this, but I don't want to:

Code:

---

int Add(int num1, int num2)
{
    int sum;
   
    sum=num1+num2;
   
    cout << sum;
}

---

I tried 'couting' a function with a return value, and this works, but is this legal?

EDIT - Whoops. I completely misinterpreted what you meant. Sorry.

Do what Mario said. Alternatively -

Quote:

---

int Result = Add( 4, 2 );
std::cout<< Result;

---

But there's no reason why you should need the int variable

Code:

---

std::cout << Add(12, 23);

---

and you can remove the cout from inside the function

Code:

---

int Add(int num1, int num2)
{
    int sum;
   
    sum=num1+num2;
   
    cout << sum;
}

---

This code is wrong because this function should return an int.

Code:

---

int Add(int num1, int num2)
{   
    return(num1+num2);
   
}

---

This one returns the sum of its arguments so you can print them if you want.

Code:

---

cout << Add(3, 9);

---

Oh ok, so it is fine to 'cout' a function?

>> Oh ok, so it is fine to 'cout' a function?

As long as the function return something cout-able.

If I had a class like so

Code:

---

class thing
{
private:
        int MyInt;
        std::string MyString;

public
        thing();
};

---

And tried to cout an instance, it won't work. You'll have to overload a << function to define how it acts in that respect. Same with (i)(o)fstreams

as twomers said with the addition that you will not be couting a function. The function will be evaluated and it is the return value that is used by the cout object