simple array of char array problem

hi all,

I have a global array of char array like so

Code:

---

char *myArray[100];

---

I then set initialise it with memset

Code:

---

memset(myArray, '\0', sizeof(myArray));

---

Now the problem is that I have a function which is called multiple times which assigns strings the myArray like so (obviously this is a simplified version)

Code:

---

void myArrayAssignment(int i){
char buf[] = "hello world";
myArray[i] = buf;
}

---

Now the problem is that when I leave the myArrayAssignment function the variable "buf" becomes out of scope so the indexs of myArray all point to junk.

I will need to change myArray from

Code:

---

char *myArray[100];

---

to the form of something like this:

Code:

---

char myArray[100][256];

---

But i dont know how to assign to the array because C++ doesnt allow for array to array assignments.

Is there away to do this strcpy()?
Thanks

You might try strncpy()

Thanks :-)

I tried this but with no luck

Code:

---

char myArray[100][256]

void myArrayAssignment(int i){
char buf[] = "hello world";
strncpy(myArray[i], buf, strlen(buf));
}

---

Didnt work as i got the following error:
cannot convert ‘char**’ to ‘char*’ for argument ‘1’

Are you are asking for this ?

Code:

---

#include <iostream>
using namespace std;

void assign_array( char arr [][256], int i ) {
    strcpy( arr[i], "Hello world" );
}

int main() {
  char myArray[100][256];
  int i = 77;
  assign_array( myArray, i );
  cout << myArray[i] << endl;
}

---

Kurt

No, but he may be asking for this :D

Code:

---

#include <iostream>
#include <cstring>
using namespace std;

void assign_array( char arr [][256], int i ) {
    strcpy( arr[i], "Hello world" );
}

int main() {
  char myArray[100][256];
  int i = 77;
  assign_array( myArray, i );
  cout << myArray[i] << endl;
}

---

strcpy() is in <cstring>.

Why make an array of char * instead of a vector of string?