Question With Nested If's

Code:

---


scanf ("%c", i);

if (i=='a')
{
    printf ("the user enterered a thus it entered if");
          scanf ("%c", i);
          if (i=='a')
          {
                printf ("the user still entred a");
          }
}

else printf ("the user did not enter a");

---

this is a simplified form of my question, if the user did not enter 'a' on the second if statement, will it go straight to else?

problem 1:
-scanf needs the address of 'a' as in &a

but to answer your question assuming the first line works... no

Why not compile it and find out? No. The else binds to the first if.


Quzah.

Consider the following code:

PHP Code:

---

char c1, c2;

scanf("%c", &c1); /* Get a character */
scanf("%c", &c2); /* Get another character */

if (c1 == 'a')
{
    printf("User entered an 'a' first ");
    if (c2 == 'a')
    {
        printf("and also the second was an 'a'\n");
    }
    else
    {
        printf("buf the second was not an 'a'\n");
    }
}
else
{
    printf("First character was not an 'a' ");
    if (c2 == 'a')
    {
        prinf("but the second one was!\n");
    }
    else
    {
        printf("and neither was the second one!\n");
    }
} 


---

And see what the effect is .... enter every combination of a and something else and try to predict what the program will output.

i'm sorry for the first one, forgot the & in there, yes i tried to compile it but the program just crash after i entered the character..

i already tried the code above, that was my original idea for my program but then it is a very long code..i'm trying to shorten my program now..

is my question above possible? like if the second if statement is false, it will do directly to the first else?

possible?

Code:

---

scanf ("%c", &i);

if (i=='a')
{
    printf ("the user enterered a thus it entered if");
    scanf ("%c", &i);
    if (i=='a')
          printf ("the user still entred a");
}
if(i!='a')
    printf ("the user did not enter a");

---

that's one way. Although its pretty silly at this point

by the way, thanks for all the peepz helping me out here..

here's the segment of the program i'm trying to do..

Code:

---


scanf ("%c", &cAction);
if (cAction=='H' || cAction=='h') //if hte player hits
{
    //codes to deal the third card from the player..

          scanf ("%c", &cAction);
          if (cAction=='H' || cAction=='h')
          {  //codes to deal the fourth card..

          }

}

else //meaning if the user choose to stand..
{// codes to when the user stands..
}

---

the else part, where the user stands, is quite long and putting the same code all over again when it's needed will make it long, so i thought if i'll put em in a nested if, i thought that anytime the if statements inside would return false, it will immediately go to this else, i was trying to make an else statement for multiple if's!

this is a blackjack game by the way..

i cant use fuctions, it's hard to explain..

what do i do?

edit:
scratch that. I mentioned switch, but I forgot about the original requirement that it asks twice.

my thought would be to loop.
for(i=0; i < 2 && (a == 'H' || a == 'h'); i++).....

and then instead of the else, check for the condition (a == 'H' || a == 'h') in an 'if'