float vs Double

while trying the following code

Code:

---

void main()
{
 float a=0.7;
 if(0.7>a)
  printf("1");
else
printf("2");
}

---

and the output came out as 1.

can anybody tell why??

is it true that that it is due to double and float comparision.

Yup, best is to subtact the 2 and compare the absolute value to a range.

EDIT:

Why is due to how floats and doubles are stored... look into how binary decimals are calculated.

I did not try but, can a computer exactly represent 0.7 in binary? or makes its best approximation? if so, it is expexted to have a wrong result from such a comparison?

You may want to have a look binary representation of data in computers!

> void main()
main returns an int - http://faq.cprogramming.com/cgi-bin/...&id=1043284376

> if(0.7>a)
You're comparing a double constant with a float variable.
In the promotion of the float to a double, the value changes, and the expected comparison fails.

Try
if(0.7f>a)

This is sticking plaster, not a solution.
Wraithan's approach is much more sound.

> is it true that that it is due to double and float comparision.
Yes, there are many traps in floating point calculations.