allocating array of pointers

Please help me something, im being confused about that:

a code in c:

Code:

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char **array = (char**)malloc(sizeof(char*) * number);

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what would be the proper way to do this in c++?

Code:

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char **array = new char*[number];
or
char **array = new char*[sizeof(char *) * number];

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where the "number" is number of pointer.

Thanks a lot for help.

> char **array = (char**)malloc(sizeof(char*) * number);
Don't cast malloc in C - see the FAQ

char **array = new char*[number];
This one is correct.
One advantage of new is that it always knows the type of thing it allocates, so the sizeof() is implicit in every call. All you have to care about is how many you want.