two dimensional array help

Hi all hope someone can give me a few pointers.
This is what I want to achieve but don't understand.

I want to return the two dimentinal array position of the largest value in a sequence of numbers.

So here is my code so far which does not return the correct results.

Code:

---

#include <stdio.h>                //preprocessor directive to include stdio
#define NUMROWS 3                //preprocessor defines
#define NUMCOLS 3

int main()                        //ep to main
{

int i, j;                        //for loop vars
int val[NUMROWS][NUMCOLS] = {1,2,3,4,5,6,7,8,9};
int maxnumpos = val[0][0];

for(i = 0; i < NUMROWS; i++)        //start outer loop
        {
                for(j = 0; j < NUMCOLS; j++)       
                        if(val[i][j] > maxnumpos)
                                maxnumpos = val[i][j];               
        }

printf("the maximum value in the array is %d & is stored at postion %d %d\n", maxnumpos, val[i][j]);

}

---

Can anyone give me some pointers to begin to understand how to deal with this scenario, whether it is code examples or a text to read

thanks in advance for your help
:confused:

If you want to keep the position of the maximum value, you'll have to make a copy of where it is.

Code:

---

#include <stdio.h>                //preprocessor directive to include stdio
#define NUMROWS 3                //preprocessor defines
#define NUMCOLS 3

int main()        //ep to main
{

  int i, j;        //for loop vars
  int val[NUMROWS][NUMCOLS] = {1,2,3,4,5,6,7,8,9};
  int maxnumpos = val[0][0];
  int maxi = 0, maxj = 0;

  for ( i = 0; i < NUMROWS; i++ )  //start outer loop
  {
      for ( j = 0; j < NUMCOLS; j++ )
        if ( val[i][j] > maxnumpos )
        {
            maxnumpos = val[i][j];
            maxi = i;
            maxj = j;
        }
  }

  printf("the maximum value in the array is %d & is stored at postion %d %d\n",
          maxnumpos, maxi, maxj);

}

/* my output
the maximum value in the array is 9 & is stored at postion 2 2
*/

---

many thanks I see it now.
My first post got me an answer with my first reply.
:D