Lvalue required --compile error--

my source code is that:

Code:

---

class Matrixes
{

long double **data;

public :

Matrixes(int row,int column);
~Matrixes();

long double** Matrixes::get();

};



Matrixes::Matrixes(int row,int column)
{
data = new long double*[row];
for (int j = 0; j < row; j++)
data[j] = new long double[column];
}

Matrixes::~Matrixes()
{
}

long double** Matrixes::get()
{
return(data);
}




class Operations
{
public:

long double** accumulate(long double **dataC,long double **dataA,long double **dataB,int row,int column)
{
Matrixes m1(3,4); // dimension of m1 object memory allocation
m1.get()=dataA; // (1) ---------COMPILE ERROR---------
.
.
.// function code
.

return(dataC);
}


};

---

in (1) line i have came across "Lvalue required"
what does it means?
what can i solve this problem

You trying to dynamically allocate a 2D Array? try this:

Code:

---

        char **X = new char*[cols];
        *X = new char [rows];

        for        ( int i=0; i<rows; i++ )
        {
                for ( int j=0; j<cols; j++ )
                {
                        X[i][j] = '*';
                        cout<< ends << X[i][j];
                }
                cout<< endl;
        }

---

but just change the chars to doubles. Cols and Rows are parameters the user has inputted.

A function cannot be put on the left hand side of an '=' expression unless it returns a 'reference'. ???
eg:

Code:

---

int& max(int &a, int &b){  //this function can be put as it returns 'int &'
  return (a>b)? a : b;
}

---

PS: this is just a quick code... I have NOT tested it...

LVALUE is just a fancy name for things that can be put on the left hand side.
temporary objects like the double** you returned are NOT lvalue ???