encoding scheme

I'm trying to encode a file that is suppose to be read from stdin and a code file that has char value and it's corresponding binary encoding. I was wondering how would I read the data in and store it into a char array and then compare it to the huffman code?

Quote:

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how would I read the data in and store it into a char array

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getc()? Or maybe fgets()?

Create a decoding table from the chars in the code file and look up the enciphered equivalent for each character you read from stdin.

I have the following:

Code:

---

#include <iostream>
#include <stdio.h>
#include <ctype.h>

using namespace std;

int main(int argc, char *argv[])
{
    int c;
    c = getchar();

    putchar(c);
    printf("\n");
}

---

This only prints out 1 character to stdout, I'm guessing I'll need to do while( c != EOF), but when I do that, I cause an infinite loop on just printing the first character. Any suggestion on fixing this problem and storing each character into a char array and once it hits EOF it will stop and perhaps print out the char array to verify everything was read in correctly. Thanks.

This is very simple. You should be able to find something in the tutorials.

Code:

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int c;  /* must be an int to hold EOF */
do {
    c = getchar();
    if(c == EOF) break;
    putchar(c);
}

---

Quote:

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Any suggestion on fixing this problem and storing each character into a char array and once it hits EOF it will stop

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For this, use fgets(), my other suggestion.

Code:

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#include <string.h>

char s[SOME_SIZE], *p;

fgets(s, sizeof(s), stdin);
if((p = strchr(s))) *p = 0;

puts(s);

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Code:

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#include <string.h>
#include <iostream>

int main()
{
    char s[256], *p;

    fgets(s, sizeof(s), stdin);
    if((p = strchr(s,'\0'))) *p = 0;

    puts(s);

    return 0;
}

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complains about strchr, says too few args.

strchr finds a specific character in a string. What character are you trying to find?


Quzah.

Well I would like it to only terminate if it hits the EOF, else continue reading each character from stdin, even if they're spaces or n.l. and store them in a char array. In the previous post, dwks suggested to use this segment of code.

[edit]

I guess it would stop if the '\0' character is seen and then just print?

Code:

---

#include <string.h>
#include <iostream>

int main()
{
    char s[256], *p;

    fgets(s, sizeof(s), stdin);
    if((p = strchr(s,'\0'))) *p = 0;

    puts(s);

    return 0;
}

---

Problem with this, it does not capture everything from stdin, just the first line.

if I try to cat input | ./a.out

it woudl only print out the first line of input.

You still aren't doing something right. You're using strchr to search for the null character ... and then you replace it with a null character. (Well not exactly, but close. A decimal zero.) Why exactly?


Quzah.

I thought it would terminate if it sees that character. What should be the second parameter of strch() ?


[EDIT]

strch searches for a specific character, I"m trying to read in the entire file and storing it in char array so I don't think strch would even work for me.

It should be whatever character you're trying to find. Why exactly are you using strchr? Do you know?


Quzah.

Hint. Try this program to see why strchr() is handy after fgets() and to see which character you should be searching for:

Code:

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#include <stdio.h>

int main(void)
{
  char buf[10], *p;

  printf("Type something: ");
  fflush(stdout);

  fgets(buf, sizeof(buf), stdin);

  // Print the ASCII value before each character entered
  for(p = buf;*p;++p)
    printf("(%d) %c\n", *p, *p);

  return 0;
}

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Try entering something less than 9 characters long. Notice anything odd about the last character outputted?

Now try it again, but enter something longer than 8 characters.

Consult an ASCII table if you have to.

Disclaimer: The preceding program and explanation assumes you're in an ASCII environment, which you probably are.