Overloading dereferencing operator.

I posted a question similar to this earlier called "I'm making C++". Does anyone know who I can overload * (the dereference operator, not the multiplication operator) so that I can gain access to the class on the right of it. It has a strange syntax: something = *something_else_in_a_pointer. Usually something + something else would be read as something.operator+(something else). So i just need to know what the function prototype would look like.

You can get at the right hand side with the use of friend functions.....

Quote:

---

#include <iostream>

using std::cout;
using std::endl;


class tester{

friend int operator*(const tester&); //declare friend

public:
tester::tester(int x){testno = x;} //constructor

private:
int testno; //private int (data)
};

int operator*(const tester& test){
return test.testno ;

}

int main(void){

tester test1(10);

cout << "Number when overloading '*' = " << *test1 << endl;


return 0;
}

---

That's just a quick mess around by me to see if I could get it to work...... and it seems to LOL :p

HEY THANKS! I've always wondered what the pirpose of friend functions was..