Count number of uppercase words in array

We are going over csting, pointers, and references. When writing my programs, I usually start off really basic then work my way up to completion. So what I have here is basically the skeleton and my logic of what the final product should somewhat look like. Again, I need to count the # of words which begin w/ an uppercase letter only.

Code:

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#include <iostream>
#include <string>
using namespace std;

int main()
{
const int max = 50;
char message [max], ch;

cout << "enter string \n";
cin.getline(message, max);
cout << "Msg is: \n" << message << endl;

for (int i=0; message[i] !='\0'; i++)
{
ch = message [i];

if (isupper (ch))
cout << "upper, the word is "<< ch << endl;
else if (islower (ch))
cout << "lower, the word is " << ch << endl;
}
                return 0;
}

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My main issue is trying to figure out when a word begins/ends.

Quote:

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Originally Posted by stevedawg85

My main issue is trying to figure out when a word begins/ends.

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Perhaps "words" are text delimited by "spaces"?

Quote:

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My main issue is trying to figure out when a word begins/ends.

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What do you define as a word in the first place?

words:
Apple, GDFF3423, T, FrAnkiE

As long as the first letter is uppercase, it is a word. And how can i signify the end of a word? I have an idea to end when white space is first encounter but I'm not sure exactly how to write that out.

Recall that (cin >> x) reads into x and skips whitespace between 'words'.

Yah I know, thats why I'm using the array. I also asked my prof and he gave me this little hint:

Code:

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while (!isspace(yourArrayPtr) && yourArrayPtr != '\0')
{
Your code
}

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I belive this answer my question, does it :P?

If it does, all I am missing is the "yourarrayptr" How can I tell the user to input a string of unknown amount of chars and then use it as a pointer

> If it does, all I am missing is the "yourarrayptr"
Just replace it with

message[i]

and see if it makes more sense.

I tired replacing it like you said but I still cant quite figure it out. I somewhat got the program running using this bootleg version, lol:

Code:

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#include <iostream>
#include <string>
#include <cctype>
using namespace std;
void array (char b[], int *bmax);
int main ( )
{                                                        //Open main
int max=56;
char *b = new char [ max];
b=&b[0];

cout << "enter string\n";

cin.getline(b, max);

cout << "displayed: "<< endl;
for (int i=0; b [i]!= '\0'; i ++)
{                                        //open for
        cout <<  *(b +i);
}                // end for
array (b, &max);
return 0;
}                                                // end main
void array (char b[], int *bmax)
{
int count =0;
for (int i=0; i < *bmax; i ++)
        {      //Start for
if (  (  isupper(*(b+i)) && isspace (*(b+i-1))) ||  (  (isupper(*(b+i))== isupper (b[0])) && isupper(*(b+i)) && *(b+i)== b[0] )    )
{                //Start if
count ++;
}                        // close if
}                //end for
delete []b;
cout << count;
}                                //close void

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I know there is an easier way to write this but this seems to get the job done :P. Well, If you would like to help me reduce this to something simpler, you help is welcome, but here is my new concern:
How do i get the words which begins w/ a captial letter to be displayed along with the total numbers. (EX: The doG is HAPPy****2 words are The, HAPPy.

Thnx for your help and time

Use the space-button!!!

Can someone please help me. This assignment is due midnight tonight. All I'm doing is asking for help. I have tried so many things, this is like my 3rd version:

Code:

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#include <iostream>
#include <string>
#include <cctype>
using namespace std;

void array (char b[], int *bmax);

int main ( )
{                                                        //Open main
int max=56;
char *b = new char [ max];
b=&b[0];

cout << "enter string\n";
        cin.getline(b, max);
array (b, &max);
return 0;
}                                                // end main

void array (char b[], int *bmax)
{
        int count =0;
        char ch;

        ch= *(b);

        for ( *(b); ch < *bmax; b++)
        while (ch != ' ' && ch != '\n')
                {
                        if (isupper (ch))
                        {
                        count ++;
                        cout << ch;
                        }
                        break;
                }                        // close if

        delete []b;
        cout << "\n" <<count;
}                                //close void

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*edited code*

Code:

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#include <iostream>
#include <string>
#include <cctype>
using namespace std;

void array (char b[], int *bmax);


const int MaxSize = 60;

int main ( )
{//Open main

        char *buffer = new char[MaxSize];

        cout << "Please enter the string to evaluate:\n";

        cin >> noskipws;
        cin.getline(&buffer[0],MaxSize);

        cout << "Message entered is: " << buffer << "\n";

        int upcase_words = 0;
        for (int i=0; i<MaxSize && buffer[i]!='\0'; i++) {

                if (i==0 && isupper(buffer[i])) {
                        upcase_words++;
                } else if (buffer[i-1]==' ' && isupper(buffer[i])) {
                        upcase_words++;
                }
        }

        cout << upcase_words << " words start with uppercase\n";

}//close void

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Here's a working version of what you want to achieve, although it just counts the words, it does not output which words are. Plus, the code is not that good but it was written in a hurry.

[edit]

Quote:

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this is like my 3rd version

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Man i must tell you i feel really dumb for taking the time to write this code for you, if i had spotted this line before you can rest assured you would not have this code. Nevertheless i decided to leave the code, i just really hope that you take the time to try and LEARN SOMETHING from this as from what concerns me you won't get any other homework done for you...

[/edit]

THANKS SO MUCH BRO!!!!!! you dont know how much I appreciate this. Hopefully I can figuire out the other part. THANKS AGAIN!!!!!!!

Quote:

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Can someone please help me. This assignment is due midnight tonight. All I'm doing is asking for help. I have tried so many things, this is like my 3rd version:

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Sometimes you just need to take a step back and ask what you really want to do. Since you probably have submitted your assignment, I suppose it is safe to show you how your homework might have been done :)

The way I see it, this is what you want to do:
1. Read a line.
2. Print what was read (i.e. the line).
3. Count number of capitalised words in this line.
4. Print the count and the capitalised words.

#1 and #2 can be solved by using a C++ string and getline().
#3 and #4 can be solved by using a (dynamic) array to store the words.
Extracting the words from the string is perhaps the most difficult part, but formatted input with std::istream (e.g. std::cin >> x) pretty much solves that for you.

Code:

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#include <string>
#include <vector>
#include <iostream>
#include <sstream>
#include <cctype>

typedef std::string WordType;
typedef std::vector<WordType> WordListType;

int main() {
        // Get the input sentence
        std::cout << "Enter a sentence: ";
        std::string sentence;
        std::getline(std::cin, sentence);
        std::cout << "Sentence entered is: " << sentence << "\n";

        // Pass the input sentence to a stringstream
        std::stringstream wordstream(sentence);

        WordListType words;
        WordType word;

        // Extract words from the wordstream using formatted input
        while (wordstream >> word) {
                // Place capitalised words into word list
                if (std::isupper(word[0])) {
                        words.push_back(word);
                }
        }

        std::cout << "Number of capitalised words: " << words.size();

        // Print list of capitalised words unless there are none
        if (!words.empty()) {
                std::cout << "\nThe capitalised words are: ";
                for (WordListType::const_iterator i = words.begin(); i != words.end(); ++i) {
                        std::cout << *i << " ";
                }
        }

        std::cout << std::endl;
        return 0;
}

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