Conceptually simple & driving me insane

Ok maybe I've had too much coffee today, but I can't see why this:

Code:

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unsigned c = 0;

for (size_t i = 0; i < sz; i++, c++) {
    cout << " " << *(b + i);
        if (c == 2) {
            cout << "\n";
            c = 0;
        }
}

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Doesn't output how I want it to. It's a snippet from one of my debugging functions, to output the program as it appears in memory. I was fine having it all dumped on one line spaced out until I started writing larger test programs. Basically I want it in this format:

Code:

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opcode operand1 operand2
 opcode operand1 operand2
 ...

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So that's a newline every 3 items, right? Then why do I get this output?

Code:

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*** DEBUG [PROGRAM DISASSEMBLY] ***

 3 9 61442
 4 61442
 0 65535
 0 0


*** END ***

*** DEBUG [REGISTERS] ***

        R0: 9
        R1: 0
        PC: 4
        Z: 0

*** END ***

*** DEBUG [REGISTERS] ***

        R0: 10
        R1: 0
        PC: 65535
        Z: 0

*** END ***
Press any key to continue

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The first line is fine, then it all goes haywire. The 0 on the 3rd line should be at the end of the 2nd line and, well, you get the idea.

Because you set c to 0 inside the loop, and when the loop goes back to the top it gets incremented, so when the first item in the second is printed, c is 1 already. It doesn't happen the first time because the c increment is not done when the loop starts, only at the end of the loop.

Got it working:

Code:

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void CVM::DebugBlock(word* b, size_t sz, bool fileDump, char* blockName)
{
    if (! fileDump) {
        unsigned c = 0;
        bool first = true;

        cout << "\n*** DEBUG [" << blockName << "] ***\n\n";
        for (size_t i = 0; i < sz; i++, c++) {
            cout << " " << *(b + i);
            if (first) {
                if (c == 2) {
                    cout << "\n";
                    c = 0;
                    first = false;
                }
            } else {
                if (c == 3) {
                    cout << "\n";
                    c = 0;
                }
            }
        }

        cout << "\n\n*** END ***" << endl;
    } else {
        FILE* f = fopen("DebugBlock.txt", "a");

        for (size_t i = 0; i < sz; i++)
            fputc(*(b + i), f);

        fclose(f);
    }
}

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Or you could just start c off at 1 and print the newline at 3.

You could make it a bit simpler and do something like this (note this code will print a newline when i=0, before anything is outputted):

Code:

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  for (int i=0;i<num_elements;i++)
  {
    if((i%3)==0)
      std::cout<<"\n";
    std::cout<<array[i]<<' ';
  }

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Quote:

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(note this code will print a newline when i=0, before anything is outputted)

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If you don't want that to happen, change this

Code:

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if((i%3)==0)

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to

Code:

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if((i%3)==0 && i)

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