How to count the occurences of operands and operators of a program using C ??

How to count the occurences of operands and operators of a program using C programming?? I'm trying to read a from a file with coding then to count the operands and operators.Can anybody please help me.... Thanks in advanced...

What have you tried so far?

Accually i really don't have idea how to start the coding. Please guide me...

Well the first step is open the file, and print every character to the screen.
This at least verifies that you can read the file correctly, because if you can't do this then the rest of the problem will be out of reach.

Then try classifying the characters as you read them, say as a keyword, an identifier or an operator.
Again, just print out the character, and what set you decided it should belong to.

I have manage to read the coding from the file but how do i compair them with the operands and operator because i wanted to get the total number of operand. Please help.....

Code:

---

switch (readVal) {
  case '+':
  case '-':
  case '*':
  /* ...and so on */
      operatorNum++;
      newOperand = 1;
      break;
  default:    // Anything that isn't the operators you listed
      if(newOperand == 1) {
          operandNum++;
          newOperand = 0;
      }
      break;
}

---

What if i wanted to list all in another notepad than compair?? How do i do this i put all the coding into a notepad name sampel.txtthen i put all the operands and operators in another notepad name operators.txt. How do i read the operators.txt and then compair the two to get the amount of operands and operators?? Can anybody cip in and give me some ideas??? Please guide me. Thanks alot...

What you said makes no sense at all.

Are you familiar with the term "beating around the bush"? That's what you're doing, right now. You might as well come out and just ask someone to write your program for you. You haven't shown us a single line of code in the 4 posts you've had in this topic.

Code:

---

# include <stdio.h>
#include <stdlib.h>
# include <string.h>

void main (void)
{
        FILE *fin;
        char no[100];
        char i;
        char b;
        char a[10] = {"+"} ;


        fin = fopen ("2.txt","r");
        if (fin == NULL)
        {
                printf ("Error  \n");
                exit(1);
        }

        while ((fgets(no,50, fin)) != NULL)
        {
                fscanf(fin, "%c\n", &no);
                printf("%s", &no);
                printf ("\n");
        }

        for (i=0;i<5;i++)
        {
                b = strcmp ("a","no[i]");

                if (b==1)
                {
                        printf ("Found Match");
                        printf ("\n");
                }

                else
                {
                        printf ("No match");
                        printf ("\n");
                }
        }
       
        fclose(fin);

}

---

This is the code i'm try out but it only print out No match even though there is a match.

If you don't want to help you can just ignore the posting. You need not be so rude. We can judge a person by the way they talk and write...

What rude? I was telling it how it is. You're here asking a question that doesn't make sense with code that you hadn't yet shown us and yet each time you reply you wonder why you haven't gotten a direct answer, yet.

Anyway, the reason your code prints no match when there is a match is because that's what you're code says to do. strcmp() returns 0 when the two words match. Yes, I know that's a bit odd considering 0 is false, but that's how it is. Basically, it returns the difference in bytes between the two strings. If there is no difference, then they must be the same.

Code:

---

for (i=0;i<5;i++)
        {
                b = strcmp ("a","no[i]");

                if (b==0)
                {
                        printf ("Found Match");
                        printf ("\n");
                }

                else
                {
                        printf ("No match");
                        printf ("\n");
                }
        }

---

I have tried with 0 before and it print the same result so i try with 1. But both also having the same problem.

Code:

---

strcmp ("a","no[i]");

---

Unless "no[i]" is a string literal it shouldn't be under quotes. I'm guessing that it's a variable. Now for the next problem. A string name with an index yields a character.

This is a character: 'a'
This is not a character: "a"

See the difference? One is a character one is a string. strcmp() compares strings, not characters.

What you want is the good ol' comparison operator:

Code:

---

if(no[i] == 'a')

---

Thanks alot for alll your help. Have a nice day

i'm now trying to do like this. Now it can found "int", and "else", but even the other operators/operands like if, main do appear in the C program file (try.txt), it's found unmatch.

Code:

---

void main ()
{
        FILE *fin;

        fin=fopen("try.txt", "r");

        if (fin == NULL)
        {
                printf("Error\n");
                exit(1);
        }

        int i, j, c;
        char z[10][10]={"if", "int", "else", "scanf", "include", "if"};
        char hals[30];
        char a;

        while((fgets(hals,30,fin))!=NULL)

        {
                fscanf(fin, "%s", &hals);
                for (j=0; j<4; j++)
                {
                        c=strcmp(hals,z[j]);
                        if(c==0)
                                printf("Found %s\n", &z[j]);
                        else
                                printf("Cant find\n");
                }       
               
        }

        fclose(fin);
}

---