deleting only the first number in an array

i know this may seem trivial, bt everytime i program i realize how much i really don't know...anyway to the point.
I have to write a stack program for my data structures class. i have most of the stuff done, but i need to be able to delete only the first most object in the array.
ie.
an array:

2
3
5
6
7

i want only to delete the 2.
--I think my stack is a bit better vertically

thanks for any help.

Are you sure that's what you need to do? A stack usually requires that you remove the top before you remove things from the bottom, so you would have to remove 7, 6, 5 and 3 before you removed 2.

If you do need to do it, you could move each element down one spot in a loop, or create a new array and copy all but the first element over.

I've never heard of that being done. Your best bet would be to allocate a new array one element smaller than your last, assign the old array to it, starting with the second element, and deleting the entire old array.

Code:

---

#include <iostream>

const char ARRAYSIZE = 10;

int main() {
    int *Arry1, *Arry2;
   
    Arry1 = new int[ARRAYSIZE];
   
    std::cout << "Array 1:" << std::endl;
    for(int i = 0; i < ARRAYSIZE; i++) {
      Arry1[i] = i * 5;
      std::cout << Arry1[i] << ' ';     
    }
   
    Arry2 = new int[ARRAYSIZE-1];
   
    std::cout << "\n\nArray 2:" << std::endl;
    for(int i = 0; i < ARRAYSIZE-1; i++) {
      Arry2[i] = Arry1[i+1];
      std::cout << Arry2[i] << ' ';
    }
     
    delete[] Arry1;
    delete[] Arry2;

    return 0;
}

---

*Note: I'm assuming that by "delete an element" you mean physically remove from memory. I should hope a person taking a data structures class should know how to overwrite an element.

After you edited your post it is unclear how your data is stored in the array. If the 2 is at the end, then just leave it there and change the size you saved (or if you are using a sentinel, put the sentinel there). If the 2 is at the beginning of the array, then see my previous post.