turn int into 6 character array, not itoa

Does anyone know of a function that can turn an int into a five character array plus a null terminator.

e.g. If the int where 12345 it would turn it into:

Code:

---

byte[0] = 0x49;
byte[1] = 0x50;
byte[2] = 0x51;
byte[3] = 0x52;
byte[4] = 0x53;
byte[5] = 0x00;

---

or the string "12345" pluss a null terminator.

e.g. If the int where 0 it would turn it into:

Code:

---

byte[0] = 0x48;
byte[1] = 0x48;
byte[2] = 0x48;
byte[3] = 0x48;
byte[4] = 0x48;
byte[5] = 0x00;

---

or the string "00000" pluss a null terminator.

How about
sprintf( mybuff, "%05d", myInt );

thank you.

Unsafe! If myInt is greater than 99999, or less than -9999, you'll get a buffer overflow. The width specification of sprintf() is a minimum, not a maximum.

You can either range-check before the call, or make the buffer large enough to accomodate larger ints (10 digits + 1 sign + 1 NUL on 32-bit int platforms).

well the largest integer i'll ever be working with is 65535 which is less than 99999, and the smallest integer i'll ever be working with is 0 which is larger than -9999. So I don't really see what the problem is.

If you can guarantee that the integers won't even be outside that range, it's fine. (Although I still think it's a bug waiting for the next program modification to strike.)
If it's just an assumption on your part, i.e. user input touches this in any way, then it's dangerous.

If you use an unsigned short then it will never be outside the range of 0-65535.

> If you use an unsigned short then it will never be outside the range of 0-65535.
The standard doesn't limit short to 16 bits, only that it should be at least 16 bits.