pointer to multidimensional array

I'm trying to use a pointer to access an array, since I need to be able to switch between two identically-sized arrays. However, I get compiler errors when I try to reference an array to my pointer. Here is a sample of the code that I have, hopefully someone can tell me what I'm doing wrong.

Code:

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int grid[320][240];    //my array
int *grid_ptr[][240];  //my pointer

int doSomethingWithGrid(int array[][240]); //function prototype

int main()
{
    grid_ptr = &grid;    //assign pointer to grid, compile error

    doSomethingWithGrid(grid_ptr);  //func. wont take pointer
}

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What errors do you get?

Quote:

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Originally Posted by Bigbio2002

I'm trying to use a pointer to access an array, since I need to be able to switch between two identically-sized arrays. However, I get compiler errors when I try to reference an array to my pointer. Here is a sample of the code that I have, hopefully someone can tell me what I'm doing wrong.

Code:

---

int grid[320][240];    //my array
int *grid_ptr[][240];  //my pointer

int doSomethingWithGrid(int array[][240]); //function prototype

int main()
{
    //error C2440: '=' : cannot convert from 'int [320][240]' to 'int *[][240]'
    grid_ptr = grid;    //assign pointer to grid, compile error

    //error C2664: 'doSomethingWithGrid' : cannot convert parameter from 'int *[][240]' to 'int [][240]'
    doSomethingWithGrid(grid_ptr);  //func. wont take pointer
}

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ive modified my code slightly and inserted the errors before the lines they appear on. hope this helps.

Code:

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int grid[320][240];
int (*grid_ptr)[240];

int doSomethingWithGrid(int (*array)[240]);

int main()
{
  grid_ptr = grid;
  doSomethingWithGrid(grid_ptr);
}

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aha, thank you!!