y does it run fork twice

when i run this code i get the message "this is child1" twice.. its only suppose to run one time?? am i doing anything wrong

Code:

---

pid_t childpid1, childpid2;
int main()
{
printf("Create 2 processes\n");
        childpid1 = fork();
            childpid2 = fork();
int i = 0;

                        if (childpid1 == 0 && i==0)
                        {
                                printf("\nthis is child 1\0");
                               
                            };
                        if (childpid2 == 0 && i==1)
                        {
                        printf("\nthis is child 2\0");
                        };
                       
        exit(0);
}

---

> childpid2 = fork();
Because this happens in parent AND child1

> if (childpid2 == 0 && i==1)
Because i is never anything other than 0

> printf("\nthis is child 2\0")
Strings always have a \0, so there's no point in adding another one yourself.

Also, you're writing C99 code, but I don't suppose that matters to you.

yeah i know i isnt anything else then 0, but this is was a test before i added it to my program. II i can see ur point that child 2 is a parent and a child....

thanks... ill fix this straight away

i got nooo idea what c99 code is.. so i guess it doenst matter ;)

Code:

---

/* executable code above here */
int i = 0;

---

This kind of declaration is allowed in C99 but not in previous versions of ansi C (or K&R C). This isn't really an issue unless you try to use a compiler that doesn't support it, but it's nice to know these things in any case.