Overloaded operator[] question

I have a simple question but could find the answer in a thread...

I have a myString class and overloaded the operator[] with

Code:

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char& operator[](unsigned int index);
const char& operator[](unsigned int index) const;

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(Actually it's the same as in the vector class: http://www.cppreference.com/cppvecto...operators.html)

In my main Routine I have the following:

Code:

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myString test("hello");
test[0]='c';
printf("%c\n", test[0]);

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My question is, why in both cases only the first overloaded function is called... Is there a way to separate assignment and return-value?

Greetings, Dee

printf is C. :) My guess is that it takes a char, not a const char. Try writing your own function:

Code:

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void function(const char c) {
    cout << c;  // or printf
}

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Can you even do that?

Wait, I have it. Use a const object and see if the second operator[] is called.

Thanks for your answer... Yes, that was my problem. I misinterpreted the way opf the second function! It will work when I use a const object... :)

Greetings, Dee