just a quick problem

alright so in my program, the user is prompted 3 times to enter an integer value. my problem is, i don't know how to make it so that if the user inputs say a letter for instance, the program won't screw up. is there a way i can avoid that?

Use fgets() to read the input as a string, then validate and convert it.

What i/o lib do you use?

i use iostream.h.

ok so the program is simple: to calculate percentages of the gross profit of a movie company. the user is supposed to input the amount of tickets sold for seniors, adults and juniors. i have the program working properly, but i want to make it so that if the user inputs a letter or something instead of a number for the amount of tickets sold that the program will say "please enter a number" or something along those lines and then prompt the user again.

You have the

Code:

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cin>>integer;

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After that write this

Code:

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if(cin.fail())
{
      cin.clear();     
      cin.ignore(500,'\n');
    //Asking for integer again, etc.
}

---

>> i use iostream.h.

That is an old, non-standard header that doesn't work on many modern compilers. Consider using iostream instead.

Either way, siavoshkc's code is good, although I would make it a while loop and place the read directly into the control: while (!(cin >> integer)). That way it will keep prompting for a number until a number is pressed.

Daved, you mean this?

Code:

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using namespace std;
#include <iostream>

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I meant <iostream> like you have it, yes. You would normally put the using directive after the #include, and of course you don't need the using directive if you add std:: to the name of the stuff from the standard library (which is how I prefer to do it).

alright so i used the cin.ignore and it's better now because it doesn't give a random value anymore, but now i need it to reprompt the user instead of just skipping the prompt and going to the next.

>> now i need it to reprompt the user instead of just skipping the prompt and going to the next.

See my first post above. Use the read as the control of a while loop.

Code:

---

while (!(cin >> integer))
{
      cin.clear();     
      cin.ignore(500,'\n');
      // Re-prompt here.
}

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