easy help

why is not taking outputting the case values 1, 2, or 3
#include <iostream.h>
#include <conio.h>

frompto()
{
cout<<"First option\n";
return 0;
}
fromotp()
{
cout<<"Second option\n";
return 0;
}

int main()
{
char value;

cout<<"This is the AMAZING program!!\n";

cout<<"1. Transform Pounds to Ounces\n";
cout<<"2. Transform Ounces to Pounds\n";
cout<<"3. Exit the program\n";
cin>>value;

switch (value)
{
case 1:
frompto();
break;
case 2:
fromotp();
break;
case 3:
cout<<"You selected to exit the AMAZING program!!/n";
return 0;

}
return 0;
}

Alright the reason is you initialized value as a char instead of an int. I changed and it worked.

#include <iostream.h>
#include <conio.h>

int frompto();
int fromotp();

int frompto()
{
cout<<"First option\n";
return 0;
}

int fromotp()
{
cout<<"Second option\n";
return 0;
}

int main()
{
int value;

cout<<"This is the AMAZING program!!\n";

cout<<"1. Transform Pounds to Ounces\n";
cout<<"2. Transform Ounces to Pounds\n";
cout<<"3. Exit the program\n";
cin>>value;

switch (value)
{
case 1:
frompto();
break;
case 2:
fromotp();
break;
case 3:
cout<<"You selected to exit the AMAZING program!!/n";
return 0;

}
return 0;
}

kick ass,thanks dude

You are imputing the char '1', '2', or '3' and your switch is 1,2,or3.
Try switch (value)
case '1': blah etc...

that worked too, thanks